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JulsSmile [24]
3 years ago
7

There are two stable isotopes of bromine. Their masses are 78.9183 and 80.9163 amu. If the average atomic mass of bromine is 79.

9091 amu, what is the natural abundance of the heavier isotope?percent abundance of 81Br __%

Chemistry
2 answers:
tamaranim1 [39]3 years ago
6 0
Probably the answer will be 28.60 because it's a lower number
just olya [345]3 years ago
5 0

The percent abundance of ₈₁Br = 49.59%

<h3>Further explanation</h3>

The elements in nature have several types of isotopes

Isotopes are atoms whose no-atom has the same number of protons while still having a different number of neutrons.

So Isotopes are elements that have the same Atomic Number (Proton)

Atomic mass is the average atomic mass of all its isotopes

In determining the mass of an atom, as a standard is the mass of 1 carbon-12 atom whose mass is 12 amu

So the atomic mass obtained is the mass of the atom relative to the 12th carbon atom

An atomic mass unit = amu is a relative atomic mass of 1/12 the mass of an atom of carbon-12.

The 'amu' unit has now been replaced with a unit of 'u' only

for example, Carbon has 3 isotopes, namely ₆¹²C, ₆¹³C, and ₆¹⁴C

Mass atom X = mass isotope 1 . % + mass isotope 2.%

Element Bromine has two isotopes, 78.9183 and 80.9163 amu.

The average atomic mass of bromine is 79.9091 amu

For example isotopes 78.9183 = x% and isotopes 80.9163 amu = 100-x%

Mass atom element Br = mass isotope 1 . % + mass isotope 2.%

79.9091 amu = 78.9183 %x +80.9163. (100-x)%

79.9091 amu = 78.9183 %x + 80.9163 .100% - 80.9163 %x

79.9091 amu = -1.998 %x + 80.9163

-1.0072 amu = -1.998 %x

x\:=\:\frac{-1.0072}{-1.998}

%x = 0.5041

x = 50,41%

So percent abundance of ₈₁Br = 100% - 50.41% = 49.59%

<h3>Learn more</h3>

The subatomic particle that has the least mass

brainly.com/question/2224691

element 2512X

brainly.com/question/2572495

about subatomic particles statement

brainly.com/question/3176193

Keywords: mass number, atomic mass, amu, isotope, Bromine

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Hatshy [7]

Octane has a density of 0.692 g/ml at 20°C. Grams of O₂ required to burn 15.0 gal of C₈H₁₈ is 1.37868×10⁵g.

Octane is a hydrocarbon having eight carbon atoms and have single bonds only.

Given,

Density of octane = 0.692g/ml

Temperature = 20°C = 293K

Amount of Octane present = 15gal

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We know that,

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Hence, 15 gal = 56781 ml

Now let's calculate the Mass of octane required:

Mass of octane = 0.692 x 56781

Mass of octane = 39292.45 g

According to the given equation,

C₈H₁₈ + 12.5O₂ ---------> 8CO₂ + 9H₂O

Also, 114g of octane needs-------> 400g of oxygen

39292.45g of octane needs ---------> 137868.24g of oxygen

Hence, oxygen needed to burn octane is 1.37868×10⁵g

Learn more about Octane here, brainly.com/question/21268869

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4 0
2 years ago
10. (a) Describe how the structure of an alloy is different to a pure metal
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Upload file
File number limit: 1Single file size limit: 10MBAllowed file types: Word, Excel, PPT, PDF, Image, Video, Audio
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Elements may be used once, more than once or not all.. Single line text.
(1 Point)
an element with a fixed valency of 2 that not is not in group 2

Help
4 0
3 years ago
How does this action cause the skateboarder's speed to decrease?
Hitman42 [59]

Answer:

The answer is B

Explanation:

B is your answer hopes this helps you

7 0
3 years ago
How many mols of chlorine are in 120g of chlorine gas
xz_007 [3.2K]

Answer:

Number of moles of chlorine = 3.38 mol

Explanation:

Given data:

Mass of chlorine = 120 g

Moles of chlorine = ?

Solution:

Formula:

Number of moles = mass/molar mass

Molar mass of chlorine = 35.5 g/mol

Now we will put the values in formula.

Number of moles = 120 g/ 35.5 g/mol

Number of moles = 3.38 mol

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andre [41]
I believe it’s A, but i’m not fully sure so wait until someone else can answer.
4 0
3 years ago
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