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JulsSmile [24]
3 years ago
7

There are two stable isotopes of bromine. Their masses are 78.9183 and 80.9163 amu. If the average atomic mass of bromine is 79.

9091 amu, what is the natural abundance of the heavier isotope?percent abundance of 81Br __%

Chemistry
2 answers:
tamaranim1 [39]3 years ago
6 0
Probably the answer will be 28.60 because it's a lower number
just olya [345]3 years ago
5 0

The percent abundance of ₈₁Br = 49.59%

<h3>Further explanation</h3>

The elements in nature have several types of isotopes

Isotopes are atoms whose no-atom has the same number of protons while still having a different number of neutrons.

So Isotopes are elements that have the same Atomic Number (Proton)

Atomic mass is the average atomic mass of all its isotopes

In determining the mass of an atom, as a standard is the mass of 1 carbon-12 atom whose mass is 12 amu

So the atomic mass obtained is the mass of the atom relative to the 12th carbon atom

An atomic mass unit = amu is a relative atomic mass of 1/12 the mass of an atom of carbon-12.

The 'amu' unit has now been replaced with a unit of 'u' only

for example, Carbon has 3 isotopes, namely ₆¹²C, ₆¹³C, and ₆¹⁴C

Mass atom X = mass isotope 1 . % + mass isotope 2.%

Element Bromine has two isotopes, 78.9183 and 80.9163 amu.

The average atomic mass of bromine is 79.9091 amu

For example isotopes 78.9183 = x% and isotopes 80.9163 amu = 100-x%

Mass atom element Br = mass isotope 1 . % + mass isotope 2.%

79.9091 amu = 78.9183 %x +80.9163. (100-x)%

79.9091 amu = 78.9183 %x + 80.9163 .100% - 80.9163 %x

79.9091 amu = -1.998 %x + 80.9163

-1.0072 amu = -1.998 %x

x\:=\:\frac{-1.0072}{-1.998}

%x = 0.5041

x = 50,41%

So percent abundance of ₈₁Br = 100% - 50.41% = 49.59%

<h3>Learn more</h3>

The subatomic particle that has the least mass

brainly.com/question/2224691

element 2512X

brainly.com/question/2572495

about subatomic particles statement

brainly.com/question/3176193

Keywords: mass number, atomic mass, amu, isotope, Bromine

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Kryger [21]

Answer:

M₂ = 0.0745 M

Explanation:

In case of titration , the following formula can be used -

M₁V₁ = M₂V₂

where ,

M₁ = concentration of acid ,

V₁ = volume of acid ,

M₂ = concentration of base,

V₂ = volume of base .

from , the question ,

M₁ = 0.0952 M

V₁ = 38.73 mL

M₂ = ?

V₂ = 49.48 mL

Using the above formula , the molarity of ammonia , can be calculated as ,

M₁V₁ = M₂V₂  

0.0952 M * 38.73 mL = M₂* 49.48 mL

M₂ = 0.0745 M

8 0
3 years ago
4) A granola bar has a mass of 42.9 g and the granola bar contains 26.20% honey
nata0808 [166]

<u>Answer:</u>

The percentage of honey in one granola bar is 26.02 percent.  

<u>Explanation:</u>

The weight of 1 granola bar is 42.9 grams. The grams of honey that is present in one granola bar is equal to 26.02 percent of 42.9 = 11.16 g

Now the amount of honey in the factory is given as 189.5g the weight of total granola bars would be

                                     = 42.9/11.16 x 189.5= 728.25

So no. of granula bars =728.25/42.9 =16.9 that can be Approximated to nearly 17

Now if one box has 6 bars then 17 bars will have to fit inside three boxes  

7 0
3 years ago
What mass of NaNO3 must be dissolved to make 838mL of a 1.25 M solution
denis-greek [22]

Answer:

89.04 g of NaNO₃.

Explanation:

We'll begin by converting 838 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

838 mL = 838 mL × 1 L / 1000 mL

838 mL = 0.838 L

Next, we shall determine the number of mole of NaNO₃ in the solution. This can be obtained as follow:

Volume = 0.838 L

Molarity = 1.25 M

Mole of NaNO₃ =?

Mole = Molarity × volume

Mole of NaNO₃ = 1.25 × 0.838

Mole of NaNO₃ = 1.0475 mole

Finally, we shall determine the mass of NaNO₃ needed to prepare the solution. This can be obtained as follow:

Mole of NaNO₃ = 1.0475 mole

Molar mass of NaNO₃ = 23 + 14 + (16×3)

= 23 + 14 + 48

= 85 g/mol

Mass of NaNO₃ =?

Mass = mole × molar mass

Mass of NaNO₃ = 1.0475 × 85

Mass of NaNO₃ = 89.04 g

Therefore, 89.04 g of NaNO₃ is needed to prepare the solution.

4 0
3 years ago
HELPPP What method should you use to separate this sample of mixture?
kozerog [31]

Answer:

The answer to your question is: D. Fractional distillation

Explanation:

A. Column chromatography  this method is use to separate mixtures base in its capacity to be absorbed.

B. Fractional crystallization  this method use the solubility of solutes in a solvent.

C. Simple distillation  is a method to separate 2 liquids based on the difference in their boiling points.

D. Fractional distillation  is a method used to separate a mixture of liquids which have their boiling points very close.

E. Paper chromatography is a method to separate a mixture based on their different rate of migration on a paper.

8 0
3 years ago
Please help I need help
slava [35]

Answer:

Covalent

Ionic

Ionic

Ionic

Explanation:

CO_{2}  - Covalent

Rest all of them are Ionic bonds in Nature.

7 0
3 years ago
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