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JulsSmile [24]
2 years ago
7

There are two stable isotopes of bromine. Their masses are 78.9183 and 80.9163 amu. If the average atomic mass of bromine is 79.

9091 amu, what is the natural abundance of the heavier isotope?percent abundance of 81Br __%

Chemistry
2 answers:
tamaranim1 [39]2 years ago
6 0
Probably the answer will be 28.60 because it's a lower number
just olya [345]2 years ago
5 0

The percent abundance of ₈₁Br = 49.59%

<h3>Further explanation</h3>

The elements in nature have several types of isotopes

Isotopes are atoms whose no-atom has the same number of protons while still having a different number of neutrons.

So Isotopes are elements that have the same Atomic Number (Proton)

Atomic mass is the average atomic mass of all its isotopes

In determining the mass of an atom, as a standard is the mass of 1 carbon-12 atom whose mass is 12 amu

So the atomic mass obtained is the mass of the atom relative to the 12th carbon atom

An atomic mass unit = amu is a relative atomic mass of 1/12 the mass of an atom of carbon-12.

The 'amu' unit has now been replaced with a unit of 'u' only

for example, Carbon has 3 isotopes, namely ₆¹²C, ₆¹³C, and ₆¹⁴C

Mass atom X = mass isotope 1 . % + mass isotope 2.%

Element Bromine has two isotopes, 78.9183 and 80.9163 amu.

The average atomic mass of bromine is 79.9091 amu

For example isotopes 78.9183 = x% and isotopes 80.9163 amu = 100-x%

Mass atom element Br = mass isotope 1 . % + mass isotope 2.%

79.9091 amu = 78.9183 %x +80.9163. (100-x)%

79.9091 amu = 78.9183 %x + 80.9163 .100% - 80.9163 %x

79.9091 amu = -1.998 %x + 80.9163

-1.0072 amu = -1.998 %x

x\:=\:\frac{-1.0072}{-1.998}

%x = 0.5041

x = 50,41%

So percent abundance of ₈₁Br = 100% - 50.41% = 49.59%

<h3>Learn more</h3>

The subatomic particle that has the least mass

brainly.com/question/2224691

element 2512X

brainly.com/question/2572495

about subatomic particles statement

brainly.com/question/3176193

Keywords: mass number, atomic mass, amu, isotope, Bromine

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When a compound such as X2Z4 is created, what would be the<br> correct simplified chemical formula?
Shtirlitz [24]

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Ammonia can be produced in the laboratory by heating ammonium chloride
AnnyKZ [126]

Answer:

Mass = 2.89 g

Explanation:

Given data:

Mass of NH₄Cl = 8.939 g

Mass of Ca(OH)₂ = 7.48 g

Mass of ammonia produced = ?

Solution:

2NH₄Cl   +  Ca(OH)₂     →    CaCl₂ + 2NH₃ + 2H₂O

Number of moles of NH₄Cl:

Number of moles = mass/molar mass

Number of moles = 8.939 g / 53.5 g/mol

Number of moles = 0.17 mol

Number of moles of Ca(OH)₂ :

Number of moles = mass/molar mass

Number of moles = 7.48 g / 74.1 g/mol

Number of moles = 0.10 mol

Now we will compare the moles of ammonia with both reactant.

                      NH₄Cl          :          NH₃

                          2              :           2

                         0.17          :          0.17

                   Ca(OH)₂         :          NH₃

                        1                :           2

                    0.10              :          2/1×0.10 = 0.2 mol

Less number of moles of ammonia are produced by ammonium chloride it will act as limiting reactant.

Mass of ammonia:

Mass = number of moles × molar mass

Mass = 0.17 mol × 17 g/mol

Mass = 2.89 g

6 0
2 years ago
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