Answer:
T = 74°C
Explanation:
Given Mw = mass of water = 330g, Ma = mass of aluminium = 840g
Cw = 4.2gJ/g°C = specific heat capacity of water and Ca = 0.9J/g°C = specific heat capacity of aluminium
Initial temperature of water = 100°C.
Initial temperature of aluminium = 29°C
When the boiling water is poured into the aluminum pan, heat is exchanged and after a short time the water and aluminum pan both come to thermal equilibrium at a common temperature T.
Heat lost by water equal to the heat gained by aluminium pan.
Mw × Cw×(100 –T) = Ma × Ca × (T–29)
330×4.2×(100– T) = 890×0.9×(T–29)
1386(100 – T) = 801(T –29)
1386/801(100 – T) = T – 29
1.73(100 – T) = T – 29
173 –1.73T = T –29
173+29 = T + 1.73T
202 = 2.73T
T = 202/2.73
T = 74°C
Snow balls can be fun. In the winter time, and in the Turkey season
A if it is one answer and if it’s multiple choice A and D
Answer:
The value is 
Explanation:
From the question we are told that
The height of the water is 
The density of oil is 
The height of oil is 
Given that both arms of the tube are open then the pressure on both side is the same
So

=> Here

where
is the density of water with value 
and
is the atmospheric pressure
and

=> 
=> 
=> 
=> 
The difference in height is evaluated as

