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3 years ago

For f(x) = 6x + 20, what is the value of x for which f(x)= -4 ?

Mathematics

1 answer:

Ymorist [56]3 years ago

3 0

Answer:

x = -4

Step-by-step explanation:

Plug in -4 into the function and solve for x:

f(x) = 6x + 20

-4 = 6x + 20

-24 = 6x

-4 = x

So, the answer is x = -4

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Sholpan [36]

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3 years ago

Lucy has some pennies and some nickels. She has a maximum of 15 coins worth a minimum of $0.47combined.If lucky has 6.9999999999

Verdich [7]

Answer:

Step-by-step explanation:

The worth of a penny is 1 cent = 1/100 = $0.01

The worth of a nickel is 5 cents = 5/100 = $0.05

Let x represent the number of pennies that she could have. Lucy has some pennies and some nickels. She has a maximum of 15 coins. If lucky has 6.999999999999999, it means that

6.999999999999999 + x ≥ 15

x ≥ 15 - 6.999999999999999

x ≥ 8

If the 15 coins worth a minimum of $0.47combined, it means that

0.05(6.999999999999999) + 0.01x ≤ 0.47

0.35 + 0.01x ≤ 0.47

0.01x ≤ 0.47 - 0.35

0.01x ≤ 0.12

x ≤ 0.12/0.01

x ≤ 12

Therefore, the possible values for the number of pennies that she could have is 8 ≤ x ≤ 12

6 0

3 years ago

What times what equals 168 besides 84 times 2?

Art [367]

Answer:

12 & 14

Step-by-step explanation:

8 0

3 years ago

If you place a 20 ft ladder 4ft from the base of the wall. How high up will it reach? Round answer to the nearest tenth

xeze [42]

Answer:

h = 19.6 ft

Step-by-step explanation:

Given that,

A 20 ft ladder 4ft from the base of the wall.

The height of the ladder, H = 20 ft

The base distance, b = 4 ft

We need to find the height of the reach. Let it is P.

Using Pythagoras theorem,

$H^2=b^2+P^2\\\\P=\sqrt{H^2-b^2}\\\\P=\sqrt{20^2-4^2}\\\\=19.59\ ft$

P = 19.6 ft

So, the height is 19.6 ft.

7 0

3 years ago

Write the equation of the line graphed below in Point-Slope form. Use the point labeled on the graph. State the slope and point.

saw5 [17]

Given:

The graph of a line.

To find:

The point-slope form of the given line.

Solution:

From the given graph it is clear that the line passes through the point (1,5) and (0,-1). So, the slope of the line is:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

$m=\dfrac{-1-5}{0-1}$

$m=\dfrac{-6}{-1}$

$m=6$

The slope of the line is 6 and it passes through the point (1,5). So, the point slope form of the line is:

$y-y_1=m(x-x_1)$

$y-5=6(x-1)$

Therefore, the point-slope form is $y-5=6(x-1)$ , slope is 6 and the point is (1,5).

6 0

3 years ago