Answer:
601 gram
Explanation:
1st we should know how may moles are there in 1.34 X 10 25 atoms
# moles of Al = # of atoms / # of Avogadro's num
= 1.34 X 10 25/ 6.12X10 23 =
= 22.26 mol of AL
so mass of AL = moles x m.wt
=22.26 x 26.98 = 600.55 = 601 gram
DONE
A 25.00 ml sample of hydrochloric acid solution, HCl, is titrated with 0.0512 m NaOH solution. the volume of NaOH solution required is 21.68 ml then the molarity of the HCl solution is 0.044 M .
Calculation ,
Formula used : ...( i )
Where M is the molarity or concentration and V is the volume in ml .
concentration of hydrochloric acid solution ( ) = ?
concentration of NaOH ( ) = 0.0512 M
volume of hydrochloric acid solution ( ) = 25.00 ml
volume of NaOH ( ) = 21.68 ml
Putting the value of concentration , volume of both in equation ( i ) we get .
× 25.00 ml = 0.0512 × 21.68 ml
= 0.0512 × 21.68 ml / 25.00 ml= 0.044 M
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I don’t know how to help you but good luck
Answer:
the second sample has a broader range because it has more impurity by percentage
Explanation:
separation techniques
Fahrenheit (temperature) Is it asking in science?