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tatiyna
3 years ago
6

A 50kg person standing still in ice skates throws their helmet to the right at 25 m/s while on a frictionless surface. This give

s the person a speed of 1.0m/s leftwards. What is the mass of the helmet?
Consider rightward as the positive direction.
Physics
1 answer:
labwork [276]3 years ago
5 0

Answer:

2.0 kg

Explanation:

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A 1.5kw vacuum cleaner is used for half an hour. Calculate its energy usage.​
juin [17]

Answer:

its energy usage is 0.05

Explanation:

1.5kw/30=0.05

8 0
3 years ago
Two identical heavy balls are dropped from the top of the Leaning Tower of Pisa. The second ball is dropped 1 s after the first
Pepsi [2]

As the balls continue to accelerate to the ground,  the distance between them before the first ball hits the ground will increase.

<h3>What is acceleration?</h3>

Acceleration is defined as the rate change of velocity with time.

acceleration a = (Δv) / (Δt)

Two identical heavy balls are dropped from the top of the Leaning Tower of Pisa. The second ball is dropped 1 s after the first ball. The first ball start falling 1s earlier than the second ball. Thus, the acceleration for first ball will be greater than the second ball.

Thus, the distance between them before the first ball hits the ground will increase.

Learn more about acceleration.

brainly.com/question/12550364

#SPJ1

3 0
2 years ago
After hearing about an accident on his normal route, Mr. Gujral checks for alternate routes to get to work. What type of circuit
shtirl [24]

Answer:

C

Explanation:

a parallel circuit because there is more than one path

3 0
3 years ago
Block 1, of mass m1 = 2.70 kg , moves along a frictionless air track with speed v1 = 27.0 m/s . It collides with block 2, of mas
ki77a [65]

Answer:

a) Block 1 = 72.9kgm/s

Block 2 = 0kgm/s

b) vf = 1.31m/s

c) ∆KE = 936.36Joules

Explanation:

a) Momentum = mass× velocity

For block 1:

Momentum = 2.7×27

= 72.9kgm/s

For block 2:

Momentum = 53(0) (body is initially at rest)

= 0kgm/s

b) Using the law of conservation of momentum

m1u1+m2u2 = (m1+m2)v

m1 and m2 are the masses of the block

u1 and u2 are their initial velocity

v is the common velocity

Given m1 = 2.7kg, u1 = 27m/s, m2 = 53kg, u2 = 0m/s (body at rest)

2.7(27)+53(0) = (2.7+53)v

72.9 = 55.7v

V = 72.9/55.7

Vf = 1.31m/s

c) kinetic energy = 1/2mv²

Kinetic energy of block 1 = 1/2×2.7(27)²

= 984.15Joules

Kinetic energy of block 2 before collision = 0kgm/s

Total KE before collision = 984.15Joules

Kinetic energy after collision = 1/2(2.7+53)1.31²

= 1/2×55.7×1.31²

= 47.79Joules

∆KE = 984.15-47.79

∆KE = 936.36Joules

7 0
3 years ago
Define in own words.
MAVERICK [17]

A recurring illness. Typically lasts for a very long time and are very hard to remove.

6 0
4 years ago
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