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tatiyna
3 years ago
6

A 50kg person standing still in ice skates throws their helmet to the right at 25 m/s while on a frictionless surface. This give

s the person a speed of 1.0m/s leftwards. What is the mass of the helmet?
Consider rightward as the positive direction.
Physics
1 answer:
labwork [276]3 years ago
5 0

Answer:

2.0 kg

Explanation:

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If a material contains three elements but not joined in a fixed proportion it is a
iren [92.7K]
My answer -

<span> a molecule The clues are that it is elements, so that means atoms, and that it is in a fixed proportion like a molecular formula.

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4 0
3 years ago
A 1000 kg satellite and a 2000 kg satellite follow exactly the same orbit around the earth. What is the ratio F1/F2 of the gravi
Tamiku [17]

Answer:

the <em>ratio F1/F2 = 1/2</em>

the <em>ratio a1/a2 = 1</em>

Explanation:

The force that both satellites experience is:

F1 = G M_e m1 / r²       and

F2 = G M_e m2 / r²

where

  • m1 is the mass of satellite 1
  • m2 is the mass of satellite 2
  • r is the orbital radius
  • M_e is the mass of Earth

Therefore,

F1/F2 = [G M_e m1 / r²] / [G M_e m2 / r²]

F1/F2 = [G M_e m1 / r²] × [r² / G M_e m2]

F1/F2 = m1/m2

F1/F2 = 1000/2000

<em>F1/F2 = 1/2</em>

The other force that the two satellites experience is the centripetal force. Therefore,

F1c = m1 v² / r    and

F2c = m2 v² / r

where

  • m1 is the mass of satellite 1
  • m2 is the mass of satellite 2
  • v is the orbital velocity
  • r is the orbital velocity

Thus,

a1 = v² / r ⇒ v² = r a1    and

a2 = v² / r ⇒ v² = r a2

Therefore,

F1c = m1 a1 r / r = m1 a1

F2c = m2 a2 r / r = m2 a2

In order for the satellites to stay in orbit, the gravitational force must equal the centripetal force. Thus,

F1 = F1c

G M_e m1 / r² = m1 a1

a1 = G M_e / r²

also

a2 = G M_e / r²

Thus,

a1/a2 = [G M_e / r²] / [G M_e / r²]

<em>a1/a2 = 1</em>

4 0
3 years ago
A planet exerts a gravitational force of magnitude 9e22 N on a star. If the planet were 2 times closer to the star (that is, if
Dmitrij [34]

To solve this problem we will use the related concepts in Newtonian laws that describe the force of gravitational attraction. We will use the given value and then we will obtain the proportion of the new force depending on the Radius. From there we will observe how much the force of attraction increases in the new distance.

Planet gravitational force

F_p = 6*10^{22}N

F_p = \frac{GMm}{R^2}

F_p = 9*10^{22}N

Distance between planet and star

r = \frac{R}{2}

Gravitational force is

F = \frac{GMm}{r^2}

Applying the new distance,

F = \frac{GMm}{(\frac{R}{2})^2}

F =  4\frac{GMm}{R^2}

Replacing with the previous force,

F = 4F_p

Replacing our values

F= 4(9*10^{22}N)

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5 0
3 years ago
Which system of measurement has been standardized worldwide for scientific uses?
belka [17]
<h2>Answer: The Systeme international (International System of Units)</h2>

The International System of Units (SI) is used in almost every country in the world (<em>except Burma, Liberia and the United States</em>).

This system was created in 1960 by the 11th General Conference of Weights and Measures in France and is made up of seven basic units:  

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-Kelvin (temperature)

-Second (time)

-Meter (length)

-Kilogram (mass)

-Candela (luminous intensity)

-Mol (amount of substance) *added to the system in 1971

Plus an unlimited number of derived units from the main ones.

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3 years ago
What is translational kinetic energy?
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power energy potential energy

7 0
3 years ago
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