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blagie [28]
3 years ago
7

How many grams are in 2 moles of copper

Chemistry
1 answer:
alisha [4.7K]3 years ago
7 0

Answer:

In 2 moles of copper, there are 319.2172 grams.

Explanation:

Quick conversion chart of moles Copper(II) Sulfate to grams 1 moles Copper(II) Sulfate to grams = 159.6086 grams 2 moles Copper(II) Sulfate to grams = 319.2172 grams

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The titration of Na2CO3 with HCl has the following qualitative profile: a. Identify the major species in solution at points A-F.
exis [7]

Answer:

Answer is explained in the explanation section below.

Explanation:

Solution:

Note: This question is incomplete and lacks very important data to solve this question. But I have found the similar question which shows the profiles about which question discusses. Using the data from that question, I have solved the question.

a) We need to find the major species from A to F.

Major Species at A:

1. Na_{2} CO_{3}

Major Species at B:

1. Na_{2} CO_{3}

2. NaHCO_{3}

Major Species at C:

1. NaHCO_{3}

Major Species at D:

1. NaHCO_{3}

2. H_{2}CO_{3}

Major Species at E:

1. H_{2}CO_{3}

Major Species at F:

1. H_{2}CO_{3}

b) pH calculation:

At Halfway point B:

pH = pKa_{1} + log[CO_{3}.^{-2}]/[HCO_{3}.^{-1}]

pH = pKa_{1} = 6.35

Similarly, at halfway point D.  

At point D,

pH = pKa_{2} + log [HCO_{3}.^{-1}]/[H2CO_{3}]

pH = pKa_{2} = 10.33

8 0
3 years ago
Potassium carbonate, K 2CO 3, sodium iodide, NaI, potassium bromide, KBr, methanol, CH 3OH, and ammonium chloride, NH 4Cl, are s
slava [35]

Answer:

Potassium carbonate (K₂CO₃)

Explanation:

The compounds dissociate into ions in water, as follows:

K₂CO₃ → 2 K⁺ + CO₃⁻    ⇒ 3 dissolved particles per mole

NaI → Na⁺ + I⁻    ⇒ 2 dissolved particles per mole

KBr → K⁺ + Br⁻   ⇒ 2 dissolved particles per mole

CH₃OH → CH₃O⁻ + H⁺  ⇒ 2 dissolved particles per mole

NH₄Cl → NH₄⁺ + Cl⁻   ⇒ 2 dissolved particles per mole

Therefore, the largest number of dissolved particles per mole of dissolved solute is produced by potassium carbonate (K₂CO₃).

3 0
3 years ago
The heat of fusion for a substance is 122 joules per gram. How many joules of heat are need to melt 7.50 grams of this substance
daser333 [38]
<h3>Answer:</h3>

915 Joules

<h3>Explanation:</h3>
  • The heat of fusion is the heat that is required to convert a given mass of a substance from solid state to liquid state without change in temperature.
  • In this case, we are given specific heat of a substance as 122 joules per gram
  • It means that amount of heat equivalent to 122 joules is required to change 1 gram of the substance from solid state to liquid state.
  • Therefore, we can determine the amount of heat needed to change 7.5 grams of the substance from solid to liquid state.

1 g = 122 Joules

7.5 g = ?

       = 122 × 7.5

      = 915 Joules

Thus, 7.5 g of the substance at its melting point will require 915 Joules of heat to melt.

4 0
3 years ago
How many electrons in an atom can have the following quantum
gavmur [86]

The answer for the following question is explained.

<u><em>Therefore the  number of electrons present with the values n = 5, l = 2, m = -2, s = +1/2 is</em></u><u> </u><u><em>one(1).</em></u>

Explanation:

Here;

n represents the principal quantum number

l represents the Azimuthal quantum number

m represents magnetic quantum number

s represents spin quantum number

n = 5,

l = 2,

m = -2,

s = +1/2

Here, it implies 5d orbital.

In the  5d  orbital, 10 electrons.

As the magnetic quantum number is -2, and so it can have 1 electron.

<u><em>Therefore the  number of electrons present with the values n = 5, l = 2, m = -2, s = +1/2 is</em></u><u> </u><u><em>one(1)</em></u>

7 0
3 years ago
A mixture of methane and carbon dioxide gases contains methane at a partial pressure of 431 mm Hg and carbon dioxide at a
KatRina [158]

Answer:

XCH₄ = 0.461

XCO₂ = 0.539

Explanation:

Step 1: Given data

  • Partial pressure of methane (pCH₄): 431 mmHg
  • Partial pressure of carbon dioxide (pCO₂): 504 mmHg

Step 2: Calculate the total pressure in the container

We will sum both partial pressures.

P = pCH₄ + pCO₂

P = 431 mmHg + 504 mmHg = 935 mmHg

Step 3: Calculate the mole fraction of each gas

We will use the following expression.

Xi = pi / P

XCH₄ = pCH₄/P = 431 mmHg/935 mmHg = 0.461

XCO₂ = pCO₂/P = 504 mmHg/935 mmHg = 0.539

3 0
3 years ago
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