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AleksAgata [21]
3 years ago
8

The circles in the diagrams below represent energy levels in an atom, and the arrows show electron (blue dot) transitions from o

ne energy level to another. (the spacing between circles represents differences in energy: a larger spacing means a greater difference in energy.) assuming that the transitions occur as photons are emitted, rank the atoms based on the photon energy, from highest to lowest. hints

Chemistry
1 answer:
Hoochie [10]3 years ago
6 0
Ranking of the atom from highest to lowest is as follows:
Highest
Arrow = from outer edge to center
2nd Highest
Arrow = second closest ring to the outer edge to center
3rd Highest
Arrow = middle circle to center
Lowest
Arrow = outer edge to middle circle

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How does H3PO ionize in water ?
Nonamiya [84]

Answer:

H3PO4 + H2O ↔ H^{+} + H2PO4^{-}

Explanation:

HNO3 → NO2 + H2O + O2

H2SO4 → SO3 + H2O + O2

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How much heat is released when 1.4 mol of hydrogen fluoride are produced? H2(g) +F2(g) → 2HF(g) +536kJ (Please show work)
polet [3.4K]

Answer:

375.2 kJ

Explanation:

  • H₂(g) +F₂(g) → 2HF(g) +536kJ

The information the equation above provides lets us know that when 2 mol of hydrogen fluoride (HF) are produced, 536 kJ of energy (as heat) is produced.

We can then <u>state a rule of three</u>:

  • 2 mol HF --------  536 kJ
  • 1.4 mol HF --------- X

And <u>solve for X</u>:

  • X = 1.4 mol * 536 kJ / 2 mol
  • X = 375.2 kJ
7 0
3 years ago
Distinguish between mass and weight
yKpoI14uk [10]

Answer:

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3 0
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Determing Valence Electrons
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In a chemical reaction, substrate molecule A is broken down to form one molecule of product B and one molecule of product C. The
MAVERICK [17]

Answer:

The answer to your question is d. 0.5 M

Explanation:

Data

[A] = 1M

K = 0.5

Concentration of B and C at equilibrium = x

Concentration of A at equilibrium = 1 - x

Equation of equilibrium

                                       k = \frac{[B][C]}{A}

Substitution

                                       0.5 = \frac{[x][x]}{1 - x}

Simplification

                                       0.5 = \frac{x^{2}}{1 - x}

Solve for x

                                      0.5(1 - x) = x²

                                      0.5 - 0.5x = x²

                                       x² + 0.5x - 0.5 = 0

Find the roots             x₁ = 0.5     x₂ = -1

There are no negative concentrations so the concentration of A at equilibrium is  

                       [A] = 1 - 0.5

                             = 0.5 M

4 0
3 years ago
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