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2 years ago

9. What coefficient of H+ balances the atoms in this half-reaction? H+ + MnO₂ → Mn²+ + H₂O

Chemistry

1 answer:

algol132 years ago

7 0

Answer:4

Explanation:To balance the equation you need to make the number of each element equivalent in both sides.

To start add a 2 in front of the MnO2 which balances the Mn.

Then balance the oxygen by adding a 4 in front of H20.

The H then needs a 8 as it’s coefficient.

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Determine the amount in grams of kcl that exists in 20.3 g of a solution that contains 1.14 % KCI by mass.

artcher [175]

Answer:

0.23 g

Explanation:

From the question given above, the following data were obtained:

Mass of solution = 20.3 g

Percentage by mass of KCl = 1.14%

Mass of KCl =?

The mass of KCl in the solution can be obtained as follow:

Percentage by mass = mass of solute / mass of solution × 100

1.14% = mass of KCl / 20.3

Cross multiply

Mass of KCl = 1.14% × 20.3

Mass of KCl = 1.14/100 × 20.3

Mass of KCl = 0.0114 × 20.3

Mass of KCl = 0.23 g

Therefore, the mass of KCl in the solution is 0.23 g

6 0

3 years ago

When hexan-1-ol is treated with conc. h2so4 at moderate temperatures, ________ is formed via a(n) ________ mechanism

natita [175]

When hexan-1-ol is treated with conc. H₂SO₄ at moderate temperatures, Di-n-hexyl ether is formed via SN₂ mechanism.

SN₂ Mechanism is mechanism involving the factors of steric hindrance following the order of 1° > 2° > 3°. It is a Nucleophilic substitution reaction.

Williamson Ether Synthesis is the synthesis of ether through SN₂ mechanism in which an ether is treated with conc. H₂SO₄ at moderate temperature.

When hexan-1-ol is treated with conc. H₂SO₄ at moderate temperatures, Di-n-hexyl ether is formed as below:

CH₃CH₂CH₂CH₂CH₂CH₂OH +Conc. H₂SO₄-->(CH₃CH₂CH₂CH₂CH₂CH₂)₂0

Hexan-1-ol Di-n-hexyl ether

Williamson Ether Synthesis is a reaction involving a alcohol that is deprotonated to form an ether.

Learn more about Williamson Ether Synthesis here, brainly.com/question/2622808

#SPJ4

7 0

2 years ago

Silver sulfadiazine burn-treating cream creates a barrier against bacterial invasion and releases antimicrobial agents directly

trapecia [35]

Answer : The mass of silver sulfadiazine produced can be, 71.35 grams.

Solution : Given,

Mass of $Ag_2O$ = 25.0 g

Mass of $C_{10}H_{10}N_4SO_2$ = 50.0 g

Molar mass of $Ag_2O$ = 231.7 g/mole

Molar mass of $C_{10}H_{10}N_4SO_2$ = 250.3 g/mole

Molar mass of $AgC_{10}H_{9}N_4SO_2$ = 357.1 g/mole

First we have to calculate the moles of $Ag_2O$ and $C_{10}H_{10}N_4SO_2$ .

$\text{ Moles of }Ag_2O=\frac{\text{ Mass of }Ag_2O}{\text{ Molar mass of }Ag_2O}=\frac{25.0g}{231.7g/mole}=0.1079moles$

$\text{ Moles of }C_{10}H_{10}N_4SO_2=\frac{\text{ Mass of }C_{10}H_{10}N_4SO_2}{\text{ Molar mass of }C_{10}H_{10}N_4SO_2}=\frac{50.0g}{250.3g/mole}=0.1998moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$Ag_2O(s)+2C_{10}H_{10}N_4SO_2(s)\rightarrow 2AgC_{10}H_9N_4SO_2(s)+H_2O(l)$

From the balanced reaction we conclude that

As, 2 mole of $C_{10}H_{10}N_4SO_2$ react with 1 mole of $Ag_2O$

So, 0.1998 moles of $C_{10}H_{10}N_4SO_2$ react with $\frac{0.1998}{2}=0.0999$ moles of $Ag_2O$

From this we conclude that, $Ag_2O$ is an excess reagent because the given moles are greater than the required moles and $C_{10}H_{10}N_4SO_2$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $AgC_{10}H_9N_4SO_2$

From the reaction, we conclude that

As, 2 mole of $C_{10}H_{10}N_4SO_2$ react with 2 mole of $AgC_{10}H_9N_4SO_2$

So, 0.1998 mole of $C_{10}H_{10}N_4SO_2$ react with 0.1998 mole of $AgC_{10}H_9N_4SO_2$

Now we have to calculate the mass of $AgC_{10}H_9N_4SO_2$

$\text{ Mass of }AgC_{10}H_9N_4SO_2=\text{ Moles of }AgC_{10}H_9N_4SO_2\times \text{ Molar mass of }AgC_{10}H_9N_4SO_2$

$\text{ Mass of }AgC_{10}H_9N_4SO_2=(0.1998moles)\times (357.1g/mole)=71.35g$

Therefore, the mass of silver sulfadiazine produced can be, 71.35 grams.

8 0

3 years ago

All of the Gathered in an investigation must be recorded. (Fill in the blank)

Zigmanuir [339]

The answer is "Incidents"

4 0

4 years ago

PLZ HELP THIS IS DUE RN!!!!!! NO ONE IS HELPING ME :(

Juli2301 [7.4K]

Answer:

Eght: 0

Explanation:

The work formula is W = F*d where d is displacement (which means the direction matters)

Same amount of work.

Eight

Time does not matter in Work. Force and Distance do.

F = 50 N

s = 0 The only work you have done is move the ball above your head. Thereafter you just held it.

t = 15 but no work is done. Tell your tired muscles that as they try and deal with holding a 5 kg mass above you head.

W = 0

Nine

Again from the last question you should be able to tell that time does not matter. The force is the same for both of you (that's why he's your identical twin).

So the work is the same. You both weigh the same. You both went the same distance.

4 0

3 years ago