Someone help please !!

A stiff wire 44.0 cm long is bent at a right angle in the middle. One section lies along the z axis and the other is along the l

Helga [31]

The magnitude of force acting on wire will be 1.90 N and the direction of the force acting on the wire will be 41.9 degrees below the negative y axis.

Explanation:

It is known that the force acting on a current carrying conductor placed in a magnetic field is

$F=BIL sin theta$

Here B is the magnetic field, I is the current flowing through the wire and L is the length of the wire which is given as 44 cm.

Since the wire is bended in the middle at right angle so the length of the two sides of the wire will be 22 cm each. Also one part is lying over z axis and another part lies in the plane of xy in the equation of line y = 2x. So the slope of this wire will be

$\frac{y}{x} =2$

This will be equal to tan θ.

So θ = tan⁻¹ (2) =63.4°

Then, the length of the wire will be written as components of i, j and k.

$L = (-22)k+(22) cos ( 63.4) i+(22) sin (63.4)j$

$L = 0.098 i+0.197 j-0.22k$

Then,

F = I (L × B)

$F = 20.5 ((0.0985 i + 0.197 j -0.22k) * (0.316 i))$

$F = 20.5 (\left[\begin{array}{ccc}i&j&k\\0.098&0.197&-0.22\\0.316&0&0\end{array}\right] )$

$F = 20.5(i(0)-j(0-(-0.22*0.316))+k(0-(0.316*0.197))) = 20.5(-0.069 j-0.062 k)$

$F = -1.415 j-1.271 k$

The magnitude of force on the wire will be

$F = \sqrt{(-1.415)^{2}+(-1.27)^{2} } = \sqrt{3.615}=1.90 N$

And the direction can be found by the tan inverse of the ratio of k component to j component of the force.

$theta = tan-1(\frac{-1.271}{-1.415})= 41.9 degrees$

So the magnitude of force acting on wire will be 1.90 N and the direction of the force acting on the wire will be 41.9 degrees below the negative y axis.

5 0

4 years ago

the velocity of a curling stone is due east. what will be the direction of the momentum of the curling stone as it moves?

kirill [66]

East.
momentum = mass x velocity
the direction of the momentum is the same as that of velocity.

8 0

3 years ago

Read 2 more answers

Does a battery produce dc or ac? does the generator at a commercial power station produce dc or ac?

Art [367]

1) dc
2) ac

Because my dad said so

8 0

3 years ago

At an accident scene on a level road, investigators measure a car's skid mark to be 98 m long. It was a rainy day and the coeffi

shutvik [7]

Answer:

The speed of the car was 28 m/s.

Explanation:

Hi there!

The initial kinetic energy of the car, KE, is equal to the negative work, W, done by friction to bring the car to stop. Let´s write the work-energy theorem:

W = ΔKE = final kinetic energy - initial kinetic energy

In this case, the final kinetic energy is zero, then:

W = - initial kinetic energy

Since the work done by friction is negative (the work is done in opposite direction to the movement of the car), then:

Wfr = initial kinetic energy

The work done by friction is calculated as follows:

Wfr = Fr · d

Where:

Fr = friction force.

d = distance.

The friction force is calculated as follows:

Fr = N · μ

Where:

N = normal force.

μ = coefficient of friction

Since the only vertical forces acting on the car are the weight of the car and the normal force, and the car is not being accelerated in the vertical direction, the normal force has to be equal to the weight of the car (with opposite sign).

Then the friction force can be written as follows:

Fr = m · g · μ

Where:

m = mass of the car.

g = acceleration due to gravity (9.8 m/s²)

The work done by friction will be:

W = m · g · μ · d

The equation of kinetic energy is the following:

KE = 1/2 · m · v²

Where

m = mass of the car.

v = speed.

Then:

W = KE

m · g · μ · d = 1/2 · m · v²

2 · g · μ · d = v²

2 · 9.8 m/s² · 0.40 · 98 m = v²

v = 28 m/s

The speed of the car was 28 m/s.

7 0

4 years ago

Floating in deep space, you find yourself at rest next to a small asteroid. You reach out and tap the asteroid with a hammer. Wh

Andrei [34K]

Answer:

There is a force that has the same magnitude as that of the hammer applied on the astronaut and with direction away from the asteroid, movement is given by

F_hammer - F_Gravitation = m a

Explanation:

For this exercise we will propose its solution from Newton's third law, which states that every action has a reaction of equal magnitude, but felt different.

As it is in space, we must assume that it is not subject to the gravitational attraction of nearby bodies, except the asteroid that attracts it. When he extends his hand and hits the asteroid, he exerts a force on him, by Newton's third law he responds with a force of equal magnitude applied to the astronaut, therefore without the two they are not united they could separate if this force is greater than the force of universal attraction between the two.

In summary There is a force that has the same magnitude as that of the hammer applied on the astronaut and with direction away from the asteroid, movement is given by

F_hammer - F_Gravitation = m a

4 0

3 years ago