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snow_tiger [21]

3 years ago

10

What is the Energy of a wave whose frequency is 8.45 x 10^14 Hz?

1 answer:

allsm [11]3 years ago

8 0

Answer:

E = hf

E = hc/lamda

where E-energy,

h-planck's constant (6.62 x 10^-34 Js)

f- frequency ( f = c/lamda)

c-velocity of light ( 3 x 10^8 m/s)

lamda- wavelength

you can this formula to solve all the 4 questions.

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-What is the frequency of a 5.6 x 10^10 cm wave? <br> -What is the wavelength of 0.1096 Hz wave?

bixtya [17]

The equation that we will use to solve these two questions is:
c = lambda * f where:
c is the speed f the wave
lambda is the wavelength of the wave
f is the frequency of the wave

Question 1:
we want to find f
c is assumed to be the speed of light = 3*10^8 m/sec
lambda = 5.6 * 10^10 cm = 560 * 10^6 meters
Substitute in the equation to get f as follows:
3*10^8 = 560*10^6*f
f = (3*10^8) / (560*10^6) = 0.5357 Hz

Question 2:
we want to find lambda
c is assumed to be the speed of light = 3*10^8 m/sec
f is given as 0.1096 Hz
Substitute in the equation to get lambda as follows:
3*10^8 = lambda * 0.1096
lambda = (3*10^8) / (0.1096) = 2.737226*10^9 meters

3 0

3 years ago

Starch is considered a biological polymer because it contains repeating units (C6H10O5)n.

evablogger [386]

The answer for the question is true

7 0

3 years ago

Read 2 more answers

If you answer and explain I will give 25 points!

snow_tiger [21]

Answer:535.5g

Explanation:

1) find the volume of the object

=L*W*H

=1.8*3.5*10.0

=63cm^3

2) the original formula is solving for the dencity which we have so...

D=M/V

M=D*V

M=8.5(63)

M=535.5g

7 0

3 years ago

Determine the value of the equilibrium constant, Kgoal, for the reaction

hodyreva [135]

Answer:

Part A

$K_{goal}= 3.22\times 10 ^{-66}$

Part B

$K_{goal}= 2.26\times10^{-21}$

Explanation:

Part A:

The given equation is not balanced. So, initially let's balance the equation by taking 24 moles of each of the reagent and NO.

24N₂ + 24H₂O ⇌ 24NO + 12N₂H₄

Now, simplify the equation by dividing both sides by 12. The final balanced equation is the following

2N₂ + 2H₂O ⇌ 2NO + N₂H₄

The above-balanced equation can be solved algebraically to obtain the required Kgoal value.

Adding given equations 1, 2 and 3 we obtain the required equation.

When the equations are added, the equilibrium constants of each equation are multiplied. Mathematically it can be represented as,

$K_1 \times K_2 \times K_3 = K_{goal}$

$K_{goal}= 4.10 \times 10^{-31} \times 7.40 \times 10^{-26} \times 1.06 \times 10^{-10}$

$K_{goal}= 3.22\times 10 ^{-66}$

Part B:

The required equation is balanced, Now

Let.

P₄(s)+6Cl₂(g) ⇌ 4PCl₃(g), K₁=2.00×10¹⁹ ------------------------------------ (a)

PCl₅(g) ⇌ PCl₃(g)+Cl₂(g), K₂=1.13×10⁻² --------------------------------------- (b)

By multiplying equation 2 by 4 and subtracting equation 1 from it, we get

4PCl₅(g) ⇌ P₄(s)+10Cl₂(g)

The Kgoal for the above equation is the product of four times K₂ and inverse K₁ according to the applied operation. Mathematically,

$K_{goal}= 4K_2 \times \frac{1}{K_1}$

$K_{goal}= 4(1.13\times10^{-2}) \times \frac{1}{2.00\times10^{19}}$

$K_{goal}= 2.26\times10^{-21}$

5 0

3 years ago

PLZ HELP PLZ<br> NO WRONG ANSWERS

baherus [9]

The answer to the question is D

3 0

3 years ago

Read 2 more answers