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snow_tiger [21]
3 years ago
10

What is the Energy of a wave whose frequency is 8.45 x 10^14 Hz?

Chemistry
1 answer:
allsm [11]3 years ago
8 0

Answer:

E = hf

E = hc/lamda

where E-energy,

h-planck's constant (6.62 x 10^-34 Js)

f- frequency ( f = c/lamda)

c-velocity of light ( 3 x 10^8 m/s)

lamda- wavelength

you can this formula to solve all the 4 questions.

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18.2L of gas at 95°C and 760 torr is placed in a 15L container at 80 degrees * C ; what is the new pressure ?
romanna [79]

Answer:

884.56 torr

Explanation:

Formula: \frac{P_{1}V_{1} }{T_{1}} = \frac{P_{2}V_{2} }{T_{2}}

P = Pressure

V = Volume

T = Temperature in kelvin (Celsius + 273.15)

\frac{(760)(18.2) }{368.15} = \frac{P(15) }{353.15}

P = \frac{(760)(18.2)(353.15) }{(368.15)(15)}

P = 884.56169

4 0
2 years ago
Different microscopic organisms cause different
lozanna [386]

Answer/Explanation:

A theory has lots of scientific evidence to back it up. We know this to be true based on lots of different diseases and studies of their spread.

A hypothesis is more of a starting point - an educated guess based on limited evidence. It requires further testing before becoming a theory.

A law is something that can be generalized to lots of contexts, and is universal. Such as the law of thermodynamics.

5 0
2 years ago
gas-to-liquid synfuel production can produce diesel, naptha and paraffin. The formation of these products usually involves _____
steposvetlana [31]
The second option is wrong

6 0
3 years ago
what is the concentration of hydroxide ions after 50.0 ml of 0.250 m naoh is added to 120 ml of 0.200 m na2so4? please show all
Galina-37 [17]

The concentration of the hydroxide ions after 50 ml of 0.250M NaOH is added to 120ml of 0.200M Na2SO4 is 7.35 x 10^-2 M.

What is meant by concentration?

Concentration is the total amount of solute present in the given volume of solution. this is expressed in terms of molarity, molality, mole fraction, normality etc. The term concentration mostly refers to the solvents and solutes present in the solution.

Concentration of hydroxide ions can be calculated by,

M (OH^-) = V (NaOH) x M (NaOH) / V (total) = 50ml x 0.250M / 50ml + 120ml = 0.0735M = 7.35 x 10^-2 M.

where M (OH^-) = concentration of hydroxide ions, V(NaOH) = volume of NaOH, M(NaOH) = concentration of NaOH.

Therefore, the concentration of the hydroxide ions after 50 ml of 0.250M NaOH is added to 120ml of 0.200M Na2SO4 is 7.35 x 10^-2 M.

To learn more about concentration click on the given link brainly.com/question/17206790

#SPJ4

5 0
8 months ago
HELP! Give the molar mass of Copper (II) Hydroxide.
yarga [219]

Answer:

97.561 g/mol

Explanation:

8 0
2 years ago
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