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patriot [66]
3 years ago
8

Helpp!! how much energy is required to heat up 100.0 grams of water from 0.000C to 60.00C?

Chemistry
1 answer:
disa [49]3 years ago
8 0

Answer:

25,104

Explanation:

100.0 x 4.184 x 60.0 = 25,104

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bazaltina [42]
Mole ratio:

MgCl₂ + 2 KOH = Mg(OH)₂ + 2 KCl

2 moles KOH ---------------- 1 mole Mg(OH)₂
moles KOH ------------------- 4 moles Mg(OH₂)

moles KOH = 4 x 2 / 1

= 8 moles of  KOH

molar mass KOH = 56 g/mol

mass of KOH = n x mm

mass of  KOH = 8 x 56

= 448 g of KOH 

hope this helps!

3 0
3 years ago
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650.J is the same amount of energy as? <br>2720cal<br>1550cal<br>650.cal<br>2.72cal
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<u>Ans: 650 J = 155 calories</u>


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