The frequency of a wave is just the reciprocal of the period.
For this one . . .
Frequency = 1/(period) = 1/(5 sec) = 0.2 per sec (0.2 Hz) .
Depends on the sandwich, PB&J requires peanut butter and jelly and a butter knife and a piece of bread.
Answer:
9) a = 25 [m/s^2], t = 4 [s]
10) a = 0.0875 [m/s^2], t = 34.3 [s]
11) t = 32 [s]
Explanation:
To solve this problem we must use kinematics equations. In this way we have:
9)
a)

where:
Vf = final velocity = 0
Vi = initial velocity = 100 [m/s]
a = acceleration [m/s^2]
x = distance = 200 [m]
Note: the final speed is zero, as the car stops completely when it stops. The negative sign of the equation means that the car loses speed or slows down as it stops.
0 = (100)^2 - (2*a*200)
a = 25 [m/s^2]
b)
Now using the following equation:

0 = 100 - (25*t)
t = 4 [s]
10)
a)
To solve this problem we must use kinematics equations. In this way we have:

Note: The positive sign of the equation means that the car increases his speed.
5^2 = 2^2 + 2*a*(125 - 5)
25 - 4 = 2*a* (120)
a = 0.0875 [m/s^2]
b)
Now using the following equation:

5 = 2 + 0.0875*t
3 = 0.0875*t
t = 34.3 [s]
11)
To solve this problem we must use kinematics equations. In this way we have:

10^2 = 2^2 + 2*a*(200 - 10)
100 - 4 = 2*a* (190)
a = 0.25 [m/s^2]
Now using the following equation:

10 = 2 + 0.25*t
8 = 0.25*t
t = 32 [s]
Answer: 272.82 drop/tile
Explanation:
Given that the Rain drops fall on a tile surface at a density of 4638 drops/ft2. There are 17 tiles/ft2. How many drops fall on each tile?
Tiles/ft^2 × drop/tiles = drop/ft^2
Tiles will cancel out. Leaving the answer to be drop/ ft^2
Substitutes all the magnitude of the above units.
17 × drop/tiles = 4638
Make drop/tiles the subject of formula
Drop/tiles = 4638/17
Drop/tiles = 272.82
Therefore, 272.82 drop/tile drops fall on each tile?
The answer: Solanum tuberosum