The direction of the motion is constantly changing during
motion over any closed path, not only circular.
Answer:
The specific heat is 3.47222 J/kg°C.
Explanation:
Given that,
Temperature = 13°C
Temperature = 37°C
Mass = 60 Kg
Energy = 5000 J
We need to calculate the specific heat
Using formula of energy


Put the value into the formula


Hence, The specific heat is 3.47222 J/kg°C.
This motion of all can be divided in to two, first the upward motion and second downward motion.
In case of projectiles time taken for upward motion = time taken for downward motion.
So we have time taken for upward motion = 8.14/2 = 4.07 seconds
We have equation of motion, v = u+at, where v is the final velocity , u is the initial velocity, a is the acceleration and t is the time taken.
In case of upward motion
v = 0 m/s
t = 4.07 seconds
a = -9.8 
Substituting

So initial velocity of ball = 39.886 m/s.
Mechanical energy is the sum of kinetic energy and potential energy, or E=Ek+Ep. So Ek=(1/2)*m*v² where m is the mass of the object and v is it's velocity. Mp=m*g*h where m is the mass, g=9.81 m/s² and h is the height of the object. So after we input the numbers the total mechanical energy is
E=(1/2)*2.5*(4.5²) + 2.5*9.81*18 = 25.3125 J + 441.45 J = 466.7625 J. The correct answer is E= 466 J.
<h3>
Answer: 28 m/s</h3>
Work Shown:
- Vi = starting or initial velocity = 10 m/s
- Vf = unknown final velocity
- a = acceleration = 3 m/s^2
- t = duration of time = 6 seconds
Use those values in the following kinematic equation
Vf = Vi + a*t
Vf = 10 + 3*6
Vf = 10 + 18
Vf = 28
The final velocity is 28 m/s