14J ÷ 8.5 = 1.64705882
Remember, 1.64705882 = v², so we need to find the square root.
The square root of 1.64705882 is 1.283377894464448
Hope this helps!
Un prisma rectangular de cobre, de base igual a 36 centímetros cuadrados y una altura de 10 cm se sumerge hasta la mitad por med
1 answer:
La respuesta correcta es 180 centímetros cúbicos o 180
Explicación:
El primer paso para saber cuanto alcohol desaloja el prisma es calcular el volumen total del prisma. El volumen se puede encontrar usando la formula V (Volumen) = B (base) x h (altura). El proceso se muestra a continuación:
V = B x h
V = 36 x 10 cm
V= 360
Finalmente, el volumen total del prisma debe dividirse en 2 considerando que solo la mitad del prisma fue sumergida y esta mitad equivale al volumen del alcohol desplazado.
360 ÷ 2 = 180
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14J ÷ 8.5 = 1.64705882
Remember, 1.64705882 = v², so we need to find the square root.
The square root of 1.64705882 is 1.283377894464448
Hope this helps!
Answer:
11.25 amps
Explanation:
For transformers, the magnetic flux
Therefore;
Ф = Фmax (cosωt) = 0.21·(cos(5·t))
From Faraday's law of induction, we have;
ε = -N × dΦ/dt
Which gives;
dΦ/dt = -1.05(sin (5t) )
ε = -N × dΦ/dt = -50× -1.05(sin (5t) )
ε = 52.5(sin (5t) )
I = ε/R = 52.5(sin (5t) )/3.3 = 15.9091(sin (5t) ) amps
The peak current is therefore = 15.9091 amps
The rms current = Peak current /√2 = 15.9091/(√2) = 11.25 amps.
Answer:
1.8 m
Explanation:
Given: Glass falls from a table, smashes 0.6 seconds later
To find: How high a table is
Formula: Vv=gt, dv=1/2gt^2, t=2d/g
Solution: A table's <em>height</em> is measured from the top of the edge down to the floor. The tables are shown both have a height of 30 inches, which is common for many tables.
<u>Data</u>
- t = 0.6s
- g = 9.81 m/s²
- d = ?
<u>Equation</u>
- d =
²
<u>Math & Units</u>
- d = 4.905 (0.6²)
- d = 442.676
Hence the table is 1.8 m high
Answer:
E1 = 10.15 * 10^4 N/C
E2 = 0
E3 = 10.15 *10^4 N/C
Explanation:
Given data:
Two 13 cm-long thin glass rods ( L ) = 0.13 m
charge (Q) = +11nC
distance between thin glass rods = 4 cm .
<u>Calculate the electric field strengths </u>
electric charge due to a single glass rod in the question ( E ) =
equation 1 can be used to determine E1, E2 and E3 because the points lie within the two rods hence the net electric field produced will be equal to the difference in electric fields produced
applying equation 1 to determine E1
E1 =
( distance from 1 rod is 0.01 m and from the other rod is 0.03 )
=
= 10.15 * 10^4 N/C
applying equation 1 to determine E2
E2 =
therefore E2 = 0
E1 = E3
hence E3 = 10.15*10^4 N/C