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Archy [21]
3 years ago
13

Explain how lone pairs of electrons influence the shape of a molecule.

Chemistry
1 answer:
Ronch [10]3 years ago
3 0

Explanation:

the lone pairs will be negatively charged. these have a repulsion effect on other negatively charged electrons in the shells of atoms. picture a water molecule: the lone electron pair on the top of the oxygen will have a repulsion force on the 2 hydrogen atom's orbiting electrons to cause a bent molecular geometry.

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The chemistry of life is centered on the chemistry of the element oxygen. True False
Artyom0805 [142]
I believe the answer is true, Hope i helped! :)<span />
7 0
3 years ago
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The measurement 0.0002833g has how many significant figures?
kherson [118]

Answer:

There are seven significant figures

Explanation:

There are seven different digits within the number. Three 0s, one 2, one 8, and two 3s, adding up to seven different numbers. You exclude the first 0 when the number is a decimal, leaving seven significant figures. Hope this makes sense! :)

6 0
3 years ago
Which of the following statements is FALSE?
Alborosie

Answer:

The answer to your question is: letter E

Explanation:

A. This option is correct, the n = 3 shell only has subshells: s, p and d, and shell n = 4 or 5 have f subshell.

B. This option is true in subshell p could be at most 6 electrons and 3 suborbitals.

C. This option is correct orbital "s" is a sphere.

D. This option is correct, in subshell d could be at most 10 electrons and 5 orbitals.

E. This option is false, hydrogen only has 1 electron and then one subshell (s).

6 0
3 years ago
1.12g H2 is allowed to react with 9.60 g N2, producing 1.23 g NH3.
andriy [413]

Answer:

A. m_{NH_3}^{theo} =1.50gNH_3

B. Y=82.2\%

Explanation:

Hello!

In this case, since the undergoing chemical reaction between nitrogen and hydrogen is:

N_2+3H_2\rightarrow 2NH_3

Thus we proceed as follows:

A. Here, we first need to compute the moles of ammonia yielded by each reactant, in order to identify the limiting one:

n_{NH_3}^{by \ H_2}=1.12gH_2*\frac{1molH_2}{2.02gH_2}*\frac{2molNH_3}{3molH_2}=0.370molNH_3\\\\  n_{NH_3}^{by \ N_2}=1.23gN_2*\frac{1molN_2}{28.02gN_2}*\frac{2molNH_3}{1molN_2}=0.0878molNH_3

Thus, since nitrogen yields the fewest moles of ammonia, we realize it is the limiting reactant, so the theoretical yield, in grams, of ammonia is:

m_{NH_3}^{theo}=0.0878mol*\frac{17.04gNH_3}{1molNH_3} =1.50gNH_3

B. Finally, since the actual yield of ammonia is 1.23, the percent yield turns out:

Y=\frac{1.23gNH_3}{1.50gNH_3} *100\%\\\\Y=82.2\%

Best regards!

5 0
3 years ago
Infrared (IR) and Nuclear Magnetic Resonance (NMR) are two spectroscopic techniques you've encountered in organic chemistry I, C
zalisa [80]

Answer:

The solution to this question can be defined as follows:

Explanation:

Please find the attached file for the solution:

8 0
3 years ago
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