The formula for a diagonal of a rectangle is √w^2+h^2, with w and h being the width and height. Plug in your numbers to get √7^2+5.5^2. Simplify that into √49+30.25, then to √79.25. Use your calculator to get 8.9022. The diagonal is 8.9 feet.

5 0

3 years ago

Lily’s sister has a bag of skittles containing 3 yellow skittles, 4 red skittles, 5 green skittles, and 3 orange skittles. What

lisov135 [29]

Answer:

Read a bit so you can understand which one you want.

Percentage

15 skittles, 3 of the 15 are orange.

3 over 15, or 0.2 as a percentage.

So there is a 0.8% chance that he will NOT pick an orange skittle.

Fraction

15 skittles, 3 over 15.

3 over 15 can be 1 over 5.

So there is a 4 over 5 chance that he WONT grab an orange skittle, pretty good odds.

6 0

3 years ago

The graph of quadratic parent function f was transformed to create the graph of

Vera_Pavlovna [14]

Answer:H

Step-by-step explanation:

Y= (x+2)^2-5

2 to the left x+2=0 x=-2

5 dpwn

5 0

3 years ago

The failure of a circuit board interrupts work that utilizes a computing system until a new board is delivered. The delivery tim

Hatshy [7]

Answer:

The expected cost is 152

Step-by-step explanation:

Recall that since Y is uniformly distributed over the interval [1,5] we have the following probability density function for Y

$f_Y(y ) = \frac{1}{5-1} = \frac{1}{4}$ if $1\leq y \leq 5$ and 0 othewise. (To check this is the pdf, check the definition of an uniform random variable)

Recall that, by definition

$E(Y^k) = \int_{-\infty}^{\infty} y^kf_Y(y)dy$

Also, we are given that $C = 50+3Y+9Y^2$ . Recall the following properties of the expected value. If X,Y are random variables, then

$E(a+bX+cY) = a+bE(X)+cE(Y)$

Then, using this property we have that $E[C] = 50+3E[Y]+ 9E[Y^2]$ .

Thus, we must calculate E[Y] and E[Y^2].

Using the definition, we get that

$E[Y] = \int_{1}^{5}\frac{y}{4} dy =\frac{1}{4}\left\frac{y^2}{2}\right|_{1}^{5} = \frac{25}{8}-\frac{1}{8} = 3$

$E[Y^2] = \int_{1}^{5}\frac{y^2}{4} dy =\frac{1}{4}\left\frac{y^3}{3}\right|_{1}^{5} = \frac{125}{12}-\frac{1}{12} = \frac{31}{3}$

Then

$E(C) = 50 + 3\cdot 3 + 9 \cdot \frac{31}{3} = 152$

5 0

3 years ago

Which type of triangle if any can be formed with sides measuring 8inches +8inches+ 3 inches ​

Which type of triangle if any can be formed with sides measuring 8inches +8inches+ 3 inches