(x-1)^3 / 2 = 27
For equations like this, we want to isolate x in order to get the value of it.
First, let's multiply both sides by 2 to eliminate the fraction.
(x-1)^3 = 27(2)
Now, let's take the cube root of both sides
(x-1) = ∛(27 * 2)
Now, simplify the root
x - 1 = 3∛2
Add both sides by 1
x = 1 + 3∛2
That's your answer.
Have an awesome day! :)
Answer:
This function is a quadratic.
Explanation:
If you sketch a graph, you will see the points form a U, representing a quadratic function.
B² = 8b + 84
b² - 8b - 84 = 0
b = <u>-(-8) +/- √((8)² - 4(1)(-84))</u>
2(1)<u>
</u>b = <u>8 +/- √(64 + 336)</u>
2
b = <u>8 +/- √(400)
</u> 2<u>
</u>b = <u>8 +/- 20
</u> 2
b = 4 <u>+</u> 10
b = 4 + 10 b = 4 - 10
b = 14 b = -6
<u />
As x = 5 & z=12,
<span>2/3 = y /(xz) = y/(5*12) </span>
<span>= y/60 </span>
<span>so y / 60 = 2/3 </span>
<span>y = (2*60)/3 </span>
<span>= 40</span>
The required solution is ∠RQT = 202° and ∠QTS = 51°
<h3 />
<h3>What is a cyclic quadrilateral?</h3>
A cyclic quadrilateral is a quadrilateral which has all its four vertices lying on a circle. It is also called as inscribed quadrilateral.
Its main property is that the sum of opposite angles of inscribed quadrilateral is always 180 degrees.
Now, the given circle has a cyclic quadrilateral QRST in which it is given that ∠RQT = 202° and ∠QRS = 129°
Since,sum of the opposite angles of a cyclic quadrilateral = 180°
⇒∠QTS + ∠QRS = 180°
⇒ ∠QTS + ∠129° = 180°
⇒ ∠QTS = 180° - ∠129°
⇒ ∠QTS = 51°
Hence,the requires angles are ∠RQT = 202° and ∠QTS = 51°.
More about cyclic quadrilateral :
brainly.com/question/14323008
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