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omeli [17]
3 years ago
5

Write the rate law for the following elementary reaction:

Chemistry
1 answer:
Harrizon [31]3 years ago
6 0

Answer:

Rate law = k1 [N2O5]^2

Explanation:

Rate law only cares about reactants and rate law can only be determined experimentally or by using the coefficients of reactants in elementary reactions

If 2A---->B is an elementary reaction... rate law for this is rate=k[A]^2

So if we look at your question...2N2O5---->2N2O4 + 02 (I think you are missing O2 in question because otherwise equation is unbalanced)

Rate law = k1 [N2O5]^2

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Help ASAP!!!!!!!!!!!!!!!!!!!!!!!!!
BartSMP [9]

Answer:

ok      .

Explanation:            

3 0
3 years ago
How many neutrons does element X have if its atomic number is 31 and its mass number is 80?
MrRissso [65]

49 neutrons in each nucleus.

<h3>Explanation</h3>

For each nucleus:

Mass number = Number of protons + Number of neutrons.

The atomic number of a nucleus is the same as its number of protons. The atomic number of the nucleus here is 31. There are 31 protons in each nucleus.

  • Mass number = 80;
  • Number of protons = Atomic number = 31;
  • The number of neutrons is to be found.

Again,

Mass number = Number of protons + Number of neutrons.

80 = 31 + Number of neutrons.

Number of neutrons = 80 - 31 = 49.

5 0
3 years ago
Coffee is a solution of organic substances in water
Eduardwww [97]

Answer:

yes it is

Explanation:

8 0
3 years ago
What are the two species in highest concentration in a 0.1 M solution of lactic acid (CH3CH(OH)C00H), (Ka
rusak2 [61]

Answer:

1.4 × 10^-4.

Explanation:

C3H6O3 + H2O <======> C3H5O3^- + H3O^+ ------------------------------------------(1).

So, from the question above we are given the following parameters or data which is going to help in solving this particular Question/problem;

=>concentration of the solution of lactic acid (CH3CH(OH)C00H) = 0.1 M and pH = 2.44.

Therefore, the concentration of the hydrogen ion[H^+} can be determined from the pH formula given below;

pH = - log { H^+}.

2.44 = - log { H^+}.

Therefore, {H^+} = 0.0036 M.

From the equation (1) given above, we have that the ratio for the equilibrium reaction is 1 : 1 : 1 :1. Therefore, molarity of C3H5O3^- = 0.0036 M and the molarity of C3H6O3 =( 0.1 - 0.0036 M) = 0.0964 M at equilibrium.

Hence, ka = {C3H5O3^-} { H3O^+} /{C3H6O3} = ( 0.0036 M)^2 /(0.0964 M) = 1.4 × 10^-4.

6 0
3 years ago
What would be the mass in grams of 1.204 x 1024 molecules of sulfur dioxide
melomori [17]

Answer:

mass of sulfur = 96 g

Explanation:

no of moles of sulfur dioxide in 1.204\times 10^{24} molecules = \frac{1.204\times 10^{24}}{avagadro number }= \frac{1.204\times 10^{24}}{6.023\times 10^{23}}

                                       = 2 moles

therefore mass of sulfur dioxide = moles×atomic number

                                                      =2×(16+32)

                                                      =96

6 0
3 years ago
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