The cutoff frequency for magnesium is 8.93 x 10¹⁴ Hz.
<h3>What is cutoff frequency?</h3>
The work function is related to the frequency as
W0 = h x fo
where, fo = cutoff frequency and h is the Planck's constant
Given is the work function for magnesium is 3.70 eV.
fo = 3.7 x 1.6 x 10⁻¹⁹ / 6.626 x 10⁻³⁴
fo = 8.93 x 10¹⁴ Hz.
Thus, the cut off frequency is 8.93 x 10¹⁴ Hz.
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in a one dimensional collision, a 4kg object with 5ms^1 and 6 kg object with 2ms^1 have initial velocity, the magnitude of impulse is 12 , 18
given,
mass 1 = 4kg
mass 2 = 6kg
velocity 1 = 5ms^1
velocity 2 = 2ms^1
impulse 1 = 4*(5-2)
= 12
Impulse 2 = 6*(5-2)
= 18
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The insulin levels lead to the cause of type 2 diabetes
Answer:
Avion A (10000 meters).
Explanation:
Deje que la altura de los aviones sea A y B respectivamente.
Dados los siguientes datos;
Altura A = 10000 metros
Altura B = 33300 pies
Para encontrar el avión que voló más alto, tendríamos que hacer alguna conversión de unidades.
Conversión:
Metros a centímetros;
1 metro = 100 cm
10000 metros = 100 * 10000 = 1.000.000 centímetros.
Por lo tanto, la altura A en cm = 1,000,000 centímetros
Pies a centímetros;
1 pie = 30,48 centímetros
33300 pies = 33300 * 30,48 = 1014984 centímetros.
Por lo tanto, la altura B en cm = 1014984 centímetros.
De los cálculos anteriores, podemos deducir que el avión A voló más alto.
Answer:
B= 3.33 m T
Explanation:
Given that
Speed ,C= 6 x 10⁶ m/s
d= 1 cm = 0.01 m
V= 200 V
The electric field E given as
V= E .d
E=Electric field
d=Distance
V=Voltage
200 = 0.01 x E
E=20000 V/m
The relationship between magnetic and electric field given as
E= C x B
20000 = 6 x 10⁶ x B
B =3333.333 x 10⁻⁶ T
B= 3.33 x 10⁻³ T
B= 3.33 m T
Therefore the magnetic filed will be 3.33 m T.
