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labwork [276]
3 years ago
11

Help!! HELP HELP HELP HELP

Physics
1 answer:
Anarel [89]3 years ago
8 0

Answer:

if a red <u>gaint </u> star is large enough, it may eventually blow up in an explosion called a <u>supernova</u><u> </u> leaving behind very dense <u>neutron</u> star.

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Two identical blocks are heated to different temperatures. The blocks are placed so that they touch, and heat begins to flow bet
baherus [9]

The pair of blocks is insulated, so no energy escapes. The pair of temperatures possible is  95 +95 temperature blocks.

<h3>What is thermal equilibrium?</h3>

When two objects are in direct contact and transfer heat through conduction. When the both object attain same temperature after sometime, they are called in thermal equilibrium.

Two identical blocks are heated to different temperatures. The blocks are placed so that they touch, and heat begins to flow between blocks. The heat will continue to until and unless they have same temperatures. After they being isolated, the temperature of both will be same and no heat is transferred outside.

Thus, the pair of temperatures possible is  95 +95 temperature blocks.

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4 0
2 years ago
How high would the level be in a gasoline barometer at normal atmospheric pressure?
Sergio [31]

Answer:

h = 13.06 m

Explanation:

Given:

- Specific gravity of gasoline S.G = 0.739

- Density of water p_w = 997 kg/m^3

- The atmosphere pressure P_o = 101.325 KPa

- The change in height of the liquid is h m

Find:

How high would the level be in a gasoline barometer at normal atmospheric pressure?

Solution:

- When we consider a barometer setup. We dip the open mouth of an inverted test tube into a pool of fluid. Due to the pressure acting on the free surface of the pool, the fluid starts to rise into the test-tube to a height h.

- The relation with the pressure acting on the free surface and the height to which the fluid travels depends on the density of the fluid and gravitational acceleration as follows:

                                         P = S.G*p_w*g*h

Where,                              h = P / S.G*p_w*g

- Input the values given:

                                         h = 101.325 KPa / 0.739*9.81*997

                                         h = 13.06 m

- Hence, the gasoline will rise up to the height of 13.06 m under normal atmospheric conditions at sea level.

7 0
3 years ago
A load of mass 5kg is raised through a height of 2m. calculate the work done against (g=10mls)​
Illusion [34]

The work done against gravity is 100 J

Explanation:

The work done against gravity in order to lift an object is equal to the change in gravitational potential energy of the object:

W=mg\Delta h

where

m is the mass of the object

g is the acceleration of gravity

\Delta h is the change in height of the object

For the object in this problem, we have:

m = 5 kg

g=10 m/s^2

\Delta h = 2 m

Substituting into the equation,

W=(5)(10)(2)=100 J

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3 0
3 years ago
Se lanza verticalmente una esfera con una rapidez de 30m/se. Determinar la rapidez de la esfera a una altura de 40m (g=10m/s2)
sergeinik [125]

v^2-{v_0}^2=2a(x-x_0)

dónde v es la velocidad de la esfera, v_0 es suya velocidad inicial, a=-g la aceleración debida a la gravedad, x la posición, y x_0 la posición inicial. Tomamos x_0=0\,\mathrm m a referirse a la posición de la esfera en el momento que la esfera fue lanzada.

Entonces

v^2-\left(30\,\dfrac{\mathrm m}{\mathrm s}\right)^2=2\left(-10\,\dfrac{\mathrm m}{\mathrm s^2}\right)(40\,\mathrm m)

\implies v^2=100\,\dfrac{\mathrm m^2}{\mathrm s^2}\implies v=\pm10\,\dfrac{\mathrm m}{\mathrm s}

Esto nos dice que la esfera alcanza una altura de 40 m en dos momentos - una vez hacia arriba y una vez hacia abajo. Sin embargo, independientemente del signo de la velocidad, sabemos que suya magnitud es 10 m/s, y así tenemos una rapidez de 10 m/s también en ambos momentos.

4 0
3 years ago
A car starts from rest and drives at 45 m/s in 20 s. how far did it travel
Schach [20]

Answer:

distance=speed×time.

45×20=900m.

6 0
3 years ago
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