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ArbitrLikvidat [17]
3 years ago
10

What are the key characteristics of a combustion and redox reactions?

Chemistry
1 answer:
katovenus [111]3 years ago
7 0

Answer:

Redox reactions have a reducing agent and a oxidizing agent

Explanation:the reducing agent is more reactive than the oxidizing agent

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1. a Use the valence electron molecular orbital diagram for F2 to propose ground state F2ions that satisfy the following conditi
ikadub [295]
If 2.34 moles of Mg react with 3.56 moles of l2 and 1.76 moles of Mgl2 form, what is the percent yield?
3 0
2 years ago
A breakfast of cereal, orange juice, and milk might contain 230 nutritional Calories. How much is this in Joules?
Sophie [7]

Answer:

B

Explanation:

962,320 J

230 nutritional Calories in Joules is 962,320 J

4 0
2 years ago
Which one of the following descriptions relating to nuclear reactions is correct?
monitta

Answer: option D - The total number of nucleons changes.

Explanation:

Nuclear Reaction is best described as a process such as the fission of an atomic nucleus, or the fusion of one or more atomic nuclei and / or subatomic particles in which the NUMBER of PROTONS and / or NEUTRONS in a nucleus CHANGES; the reaction products may contain a different element or a different isotope of the same element.

Note that the NUCLEONS refers to ONE of the subatomic particles of the atomic nucleus, i.e. a PROTON or a NEUTRON.

So, in a Nuclear reaction, the total number of nucleons changes.

4 0
3 years ago
Rank the following in order of increasing (lowest to highest) reactivity:
choli [55]

Answer:

a)  Li<Na<Rb

b) P<S

c) Rn<Xe

d) Hg<W<Cs

4 0
3 years ago
A pan containing 20.0 grams of water was allowed to cool from a temperature of 95.0 °C. If the amount of heat released is 1,200
34kurt

Answer:

81 °C

Explanation:

This is a calorimetry question so a few things you will need for this. The calorimetry equation q=mcΔT & the specific heat of water (4.2J/g•°C). Other definitions are:

q = heat added/released by a sample

m = mass of sample

c=specific heat of sample

ΔT = change in temperature

from here we can rearrange the equation to state:

q/(mc) = ΔT

1200J/((20.0g)(4.2J/g•°C)) = ΔT

14°C = ΔT

If the starting temperature was 95.0°C and we know that the temperature was cooled by 14°C then the final temperature of the water would be 81.

4 0
2 years ago
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