Answer:
Explanation:
Hello,
In this case, as the reaction between sodium hydroxide and sulfuric is:
We can notice a 2:1 molar ratio between the base and the acid, for that reason for the titration at the equivalence point we find:
Which in terms of concentrations and volumes is:
In such a way, solving for the required volume of base we find:
Best regards.
Answer : The mass of sodium fluoride added should be 0.105 grams.
Explanation : Given,
The dissociation constant for HF =
Concentration of HF (weak acid)= 0.0310 M
First we have to calculate the value of .
The expression used for the calculation of is,
Now put the value of in this expression, we get:
Now we have to calculate the concentration of NaF.
Using Henderson Hesselbach equation :
Now put all the given values in this expression, we get:
Now we have to calculate the moles of NaF.
Now we have to calculate the mass of NaF.
Therefore, the mass of sodium fluoride added should be 0.105 grams.