Question

Luke Autbeloe drops a pile of roof shingles from the top of a roof located 8.52

Answer 1

Answer:

t = 1.31 s

Explanation:

Given that,

The top of a roof is located 8.52  meters above the ground.

We need to find the time required for the shingles to reach  the ground. Let the time be t. Its initial velocity was 0 as it was at rest initially. Using the equation of motion to find it as follows :

$s=ut+\dfrac{1}{2}gt^2$

Where

t is the time and u = 0

$s=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2s}{g}} \\\\t=\sqrt{\dfrac{2\times 8.52}{9.8}} \\\\t=1.31\ s$

So, it will take 1.31 seconds for the shingles to reach the ground.