Accelerating at 9.8 m/s² means that every second, the speed is 9.8 m/s faster than it was a second earlier. It's not important to the problem, but this number (9.8) happens to be the acceleration of gravity on Earth.
1% of the speed of light = (300,000,000 m/s) / 100 = 3,000,000 m/s .
Starting from zero speed, moving (9.8 m/s) faster every second,
how long does it take to reach 3,000,000 m/s ?
(3,000,000 m/s) / (9.8 m/s²) = 306,122 seconds .
(That's 5,102 minutes.)
(That's 85 hours.)
(That's 3.54 days.)
Speed at the beginning . . . zero .
Speed at the end . . . 3,000,000 m/s
Average speed . . . . . 1,500,000 m/s
Distance = (average speed) x (time)
= (1,500,000 m/s) x (306,122 sec) = 4.592 x 10¹¹ meters
= 459 million kilometers
That's like from Earth
to Sun
to Earth
to Sun.
Answer:
(D) any of these objects can be used as long as all points on the object lie farther away from the lens than the focal length of the lens.
Points lying between the focal point and the lens will be erect and will not form an object visible on a screen.
nuclear energy is found in the nucleus of an atom
thermal energy is found when internal energy is transferred
Electrical energy is found in the flow of electrical charges
Chemical energy is found in the bonds between atoms
Answer:
I. Stopping acceleration = 6 m/s²
II. Stopping distance, S = 75 meters
Explanation:
Given the following data;
Final velocity = 30 m/s
Time = 5 seconds
To find the stopping acceleration;
Mathematically, acceleration is given by the equation;
Substituting into the equation;
Acceleration = 6 m/s²
II. To find the stopping distance, we would use the third equation of motion;
Where;
V represents the final velocity measured in meter per seconds.
U represents the initial velocity measured in meter per seconds.
a represents acceleration measured in meters per seconds square.
Substituting into the equation, we have;
30² = 0² + 2*6*S
900 = 12S
S = 900/12
S = 75 meters
Answer:
hiiii!
necleus and proton, electron, atom,and element
have a good day!
