Object A has a mass of 8.0 kg and is accelerating at 4.0 m/s2. Object B has a mass of 10.0 kg and is accelerating at 3.0 m/s2. O
1 answer:
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Answer:
The time taken by the brick to hit the ground, t = 0.84 s
Explanation:
Given that,
A brick falls from a height, h = 3.42 m
The initial velocity of the brick is zero.
Since the brick is under free-falling. The time equation of a free-falling body when the displacement is given is
t =
where,
h - height from surface in meters
g - acceleration due to gravity
on substituting the values in the above equation,
t =
= 0.84 s
Hence, time taken by the brick to hit the ground is t = 0.84 s
Ans: Time <span>taken by a pulse to travel from one support to the other = 0.348s
</span>
Explanation:
First you need to find out the speed of the wave.
Since
Speed = v =
Where
T = Tension in the cord = 150N
μ = Mass per unit length = mass/Length = 0.65/28 = 0.0232 kg/m
So
v =
= 80.41 m/s
Now the time-taken by the wave = t = Length/speed = 28/80.41=0.348s
</span>
Explanation:
First you need to find out the speed of the wave.
Since
Speed = v =
Where
T = Tension in the cord = 150N
μ = Mass per unit length = mass/Length = 0.65/28 = 0.0232 kg/m
So
v =
Now the time-taken by the wave = t = Length/speed = 28/80.41=0.348s