Hey here is your answer u r looking for
24.041m
Answer:
A. Time, t = 4.35s
B. Height of its fall, S = 92.72m
Explanation:
Vo = 0 m/s
Vi = 0.46h m/s
S = h m
a = 9.81 m/s2
To calculate the time taken, we need to get the value of the distance, h.
Using the equations of motion,
Vi^2 = Vo^2 + 2aS
Where Vi = final velocity
Vo = initial velocity
a = acceleration due to gravity
S = height of its fall
(0.46h)^2 = 0 + 2*9.81*h
0.2116h^2 = 19.62h
h = 19.62/0.1648
= 92.722 m
To calculate the time,
S = Vo*t +(1/2)*a*t^2
92.772 = 0 + (1/2)*9.81*t^2
t^2 = 185.44/9.81
= 18.904
t = sqrt(18.904)
= 4.348 s
True. Being an electrical engineer, you learn very quickly that current will take All paths of resistance. But, the higher the resistance the lower the voltage. So, if a high resistance is shorted and the current flows through the short, there will be some small voltage across it, so some small amount of current will still flow through the high resistance.
Answer:
B: Energy that is transformed is neither created or destroyed
Explanation:
Answer:
-4.71 m/s
Explanation:
Given:
y₀ = 1.13 m
y = 0 m
v₀ = 0 m/s
a = -9.8 m/s²
Find: v
v² = v₀² + 2a (y − y₀)
v² = (0 m/s)² + 2(-9.8 m/s²) (0 m − 1.13 m)
v = -4.71 m/s
