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Tema [17]
3 years ago
14

A pair of narrow slits, separated by 1.8 mm, is illuminated by a monochromatic light source. Light waves arrive at the two slits

in phase. A fringe pattern is observed on a screen 4.8 m from the slits.
In Situation 26.2, there are 5.0 bright fringes/cm on the screen. The wavelength of the monochromatic light is closest to:_______.
A) 550 nm
B) 600 nm
C) 650 nm
D) 700 nm
E) 750 nm
Physics
1 answer:
Katyanochek1 [597]3 years ago
5 0

Answer:

Answer:

750 nm

Explanation:

= separation of the slits = 1.8 mm = 0.0018 m

λ = wavelength of monochromatic light

= screen distance = 4.8 m

= position of first bright fringe =

= order = 1

Position of first bright fringe is given as

λ = 7.5 x 10⁻⁷ m

λ = 750 nm

Explanation:

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Answer:

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What is the relationship between air pressure and air temperature?
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A spherical capacitor is formed from two concentric sphericalconducting shells separated by vacuum. The inner sphere has radius1
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Explanation:

(1).  Formula to calculate the potential difference is as follows.

       \Delta V = -\int E dr

                  = -\int \frac{kq}{r^{2}} dr

                 = \frac{kq}{r_{f}} - \frac{kq}{r_{i}}

                 = \frac{kq(r_{f} - r_{i})}{r_{f}r_{i}}

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Therefore, magnitude of the potential difference between the two spheres is 38.7 volts.

(2).  Now, formula to calculate the energy stored in the capacitor is as follows.

           E = \frac{1}{2}QV

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              = 6.39 \times 10^{-8} J

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7 0
2 years ago
Read 2 more answers
If a soap bubble is 115 nm thick, what wavelength is most strongly reflected at the center of the outer surface when illuminated
sp2606 [1]

Answer:

611.8 nm

Explanation:

n_{oil} = Index of refraction of soap bubble  = 1.33

t = thickness of the soap bubble = 115 nm = 115 x 10⁻⁹ m

\lambda = wavelength of light = ?

m = order = 0

For reflection , the necessary condition is

2 n_{oil} t = (m + 0.5) \lambda

2 (1.33)(115\times 10^{-9})= (0 + 0.5) \lambda

\lambda = 6.118\times 10^{-7}

\lambda = 611.8 nm

7 0
2 years ago
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