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Tema [17]
3 years ago
14

A pair of narrow slits, separated by 1.8 mm, is illuminated by a monochromatic light source. Light waves arrive at the two slits

in phase. A fringe pattern is observed on a screen 4.8 m from the slits.
In Situation 26.2, there are 5.0 bright fringes/cm on the screen. The wavelength of the monochromatic light is closest to:_______.
A) 550 nm
B) 600 nm
C) 650 nm
D) 700 nm
E) 750 nm
Physics
1 answer:
Katyanochek1 [597]3 years ago
5 0

Answer:

Answer:

750 nm

Explanation:

= separation of the slits = 1.8 mm = 0.0018 m

λ = wavelength of monochromatic light

= screen distance = 4.8 m

= position of first bright fringe =

= order = 1

Position of first bright fringe is given as

λ = 7.5 x 10⁻⁷ m

λ = 750 nm

Explanation:

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Someone please help me! And I will mark you as brainlist!!
Ronch [10]

Answer:

1. G.P.E = 24 J

2. center of mass

Explanation:

Given the following data;

Mass = 2kg

Height, h = 1.2m

Acceleration due to gravity = 9.8 N/kg or m/s².

To find the gravitational potential energy;

Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.

Mathematically, gravitational potential energy is given by the formula;

G.P.E = mgh

Where;

  • G.P.E represents potential energy measured in Joules.
  • m represents the mass of an object.
  • g represents acceleration due to gravity measured in meters per seconds square.
  • h represents the height measured in meters.

Substituting into the formula, we have;

G.P.E = 2*1.2*9.8

G.P.E = 23.52 to 2 S.F = 24 Joules.

Translation kinetic energy is defined as the energy of a system due to the motion of the system’s center of mass. The center of mass is typically where the mass of the object or particle is concentrated.

6 0
2 years ago
A rocket passes you at a speed of 0.85c, and you measure its length to be 35.0 m. What is its measured length when at rest?
viktelen [127]

Answer:

66.4 m

Explanation:

To solve the problem, we can use the length contraction formula, which states that the length observed in the reference frame moving with the object (the rocket) is given by

L=L_0 \sqrt{1-(\frac{v}{c})^2}

where

L_0 is the proper length (the length measured from an observer at rest)

v is the speed of the object (the rocket)

c is the speed of light

Here we know

v = 0.85c

L = 35.0 m

So we can re-arrange the equation to find the length of the rocket at rest:

L_0 = \frac{L}{\sqrt{1-(\frac{v}{c})^2}}=\frac{35.0}{\sqrt{1-(\frac{0.85c}{c})^2}}=66.4 m

8 0
3 years ago
The end point of a spring oscillates with a period of 2.0 s when a block with mass m is attached to it. When this mass is increa
Nostrana [21]

Answer: The end point of a spring oscillates with a period of 2.0 s when a block with mass m is attached to it. When this mass is increased by 2.0 kg, the period is found to be 3.0 s.  Then the mass m is 0.625kg.

Explanation: To find the answer, we need to know more about the simple harmonic motion.

<h3>What is simple harmonic motion?</h3>
  • A particle is said to execute SHM, if it moves to and fro about the mean position under the action of restoring force.
  • We have the equation of time period of a SHM as,

                                          T=2\pi \sqrt{\frac{m}{k} }

  • Where, m is the mass of the body and k is the spring constant.
<h3>How to solve the problem?</h3>
  • Given that,

               T_1=2s\\m_1=m\\m_2=m+2kg\\T_2=3s

  • We have to find the value of m,

              T_1=2\pi \sqrt{\frac{m}{k} } \\T_2=2\pi \sqrt{\frac{m+2}{k} } \\\frac{T_1}{T_2} =\sqrt{\frac{m}{m+2} }\\\frac{2}{3} =\sqrt{\frac{m}{m+2} }\\\\

               m=\frac{5}{8} =0.625kg

Thus, we can conclude that, the mass m will be 0.625kg.

Learn more about simple harmonic motion here:

brainly.com/question/28045110

#SPJ4

3 0
2 years ago
The doppler effect is used to determine?
Korolek [52]
Uhh it is used to detirmine heat

7 0
3 years ago
Read 2 more answers
A manufacturer claims its cleanser works twice as fast as any other. Could test be performed to support the claim? Explain
lora16 [44]

Yes, a test could be performed to support the claim.

 

Hypothesis: The claim that a manufacturer’s cleanser works twice as fast as any other cleanser.

 

So, based from this hypothesis, we can perform the following tests:

We assign Cleanser A to the manufacturer that claims that their cleanser works twice as fast as any other cleanser and Cleanser B to the cleanser to be compared with.

 

1.       Get two tiles and put the same amount of stain on them.

2.       Apply Cleanser A on the first tile and Cleanser B on the second tile.

3.       Apply the same amount of force in removing the stains on both tiles

4.       Record the amount of time it takes to remove the stains on each tile.

4 0
3 years ago
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