Answer:
For bbff we have only 6.3% probability
Step-by-step explanation:
If the parents are heterozygous for both traits, them they are represented by:
BbFf × BbFf
Parent 1: BbFf
Parent 2: BbFf
We have to find the percentage of occurence of bb × ff, which is a child that has blue eyes and no freckles, with no dominant factor.
By distributing the possibilities in a Punnett square, <em>vide</em> picture. We have the following possibilities:
Genotype Count Percent
bBfF 4 25
BBfF 2 12.5
bBFF 2 12.5
bBff 2 12.5
bbfF 2 12.5
BBFF 1 6.3
BBff 1 6.3
bbFF 1 6.3
bbff 1 6.3
For bbff we have only 6.3% probability
Answer:
m-45=-78
25=x+9
x and y are proportional, because they are doubling the outcome every time by 3, so the slope would simplify to 1/4 very time.
Step-by-step explanation:
Answer:
no they are not
Step-by-step explanation:
priyas paint would be darker then mais paint because priya added an extra cup of red paint.
|3x+1|=4 : x=−
5
3 or x=1
Pasos
|3x+1|=4
Aplicar las propiedades de los valores absolutos: Pi |u| = a, a>0 entonces u = a or u = −a
3x+1=−4 or 3x+1=4
Mostrar pasos
3x+1=−4 or 3x+1=4