Answer:
Explanation:
H2SO4 let S be x
2(1) + x + 4(-2) = 0
2 + x - 8 = 0
x - 6 = 0
x = 6
For H2S7O8 let S be x
2(1) + 7(x) + 8(-2) = 0
2 + 7x - 16 = 0
7x - 14 = 0
7x = 14
x = 14/7
x = 2
:- H2SO4 as the larger percentage
This question seems to be very basic .the ocean is above the plate, the plate material is heavier than water (it being rock). That's pretty much all of it. The plates grind a little and new land pushes up at plate boundaries but this does not seem to be related. The heavier material is below and the lighter above, those being rock and water respectively.
hope this helped u
Answer:
Option D - 10,000 years ago in the Middle East
First we have to refer
to the reaction between the acid and the base: <span>
H2SO4 + 2 NaHCO3 ---> 2 H2O + 2 CO2 + Na2SO4
From this balanced equation we can see that for every 1 mol
of acid (H2SO4), we need 2 mol of base (NaHCO3) to neutralize it. Given 28 ml
of 5.8 M acid, we need to find out how many mols of acid that is:
<span>28mL * (1L/1000mL) * 5.8 mol/L = 0.1624 mol H2SO4</span></span>
<span>
Since we need 2 mol of base per mol of acid, we need:</span>
<span> 2*0.1624 mol = 0.3248 mol NaHCO3 </span><span>
MolarMass of NaHCO3 is 84.01 g/mol
<span>0.3248 mol*(84.01g/mol) = 27.29 g NaHCO3</span></span>
