Answer:
They agree to ethical standards when they are licensed.
Explanation:
Answer:
geruow0irghvn3p0unhie0ghik
Explanation:
Answer:
7
Explanation:
N-14 has 7
i looked it up ye ur probably gonna get it right
Answer:
The new equilibrium concentration of HI: <u>[HI] = 3.589 M</u>
Explanation:
Given: Initial concentrations at original equilibrium- [H₂] = 0.106 M; [I₂] = 0.022 M; [HI] = 1.29 M
Final concentrations at new equilibrium- [H₂] = 0.95 M; [I₂] = 0.019 M; [HI] = ? M
<em>Given chemical reaction:</em> H₂(g) + I₂(g) → 2 HI(g)
The equilibrium constant (
) for the given chemical reaction, is given by the equation:
![K_{c} = \frac {[HI]^{2}}{[H_{2}]\: [I_{2}]}](https://tex.z-dn.net/?f=K_%7Bc%7D%20%3D%20%5Cfrac%20%7B%5BHI%5D%5E%7B2%7D%7D%7B%5BH_%7B2%7D%5D%5C%3A%20%5BI_%7B2%7D%5D%7D)
<u><em>At the original equilibrium state:</em></u>
<u><em>Therefore, at the new equilibrium state:</em></u>
![K_{c} = \frac {[HI]^{2}}{(0.95\: M) \times (0.019\: M)}](https://tex.z-dn.net/?f=K_%7Bc%7D%20%3D%20%5Cfrac%20%7B%5BHI%5D%5E%7B2%7D%7D%7B%280.95%5C%3A%20M%29%20%5Ctimes%20%280.019%5C%3A%20M%29%7D)
![\Rightarrow K_{c} = 713.59 = \frac {[HI]^{2}}{0.01805}](https://tex.z-dn.net/?f=%5CRightarrow%20K_%7Bc%7D%20%3D%20713.59%20%3D%20%5Cfrac%20%7B%5BHI%5D%5E%7B2%7D%7D%7B0.01805%7D)
![\Rightarrow [HI]^{2} = 713.59 \times 0.01805 = 12.88](https://tex.z-dn.net/?f=%5CRightarrow%20%5BHI%5D%5E%7B2%7D%20%3D%20713.59%20%5Ctimes%200.01805%20%3D%2012.88)
![\Rightarrow [HI] = \sqrt {12.88} = 3.589 M](https://tex.z-dn.net/?f=%5CRightarrow%20%5BHI%5D%20%3D%20%5Csqrt%20%7B12.88%7D%20%3D%203.589%20M)
<u>Therefore, the new equilibrium concentration of HI: [HI] = 3.589 M</u>
Answer:
True is the correct answer to the above question.
Explanation:
- If x is a string then it can be assigned by the help of two ways in java:
- By the help of constructor:- When we write " x = new String("OH");", then it will create a pass a string "OH" into the constructor. It is because the String is a class in java and x is an object created by the constructor of the String class.
- With the help of assigning: The "x= OH", which assigns the value of x which is an object of String class it can also use the constructor to initialize the "OH" string on the class.
- The above question states the two scenarios which are defined above. Hence the question statement is true.
