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3 years ago

During which phase of the moon do spring tides typically occur

Chemistry

1 answer:

avanturin [10]3 years ago

7 0

Spring tides occur during the fullmoon and the new moon

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Given that equation Na+(s)O2–> Na2O. Find the mass of sodium needed to produce 12.5 grams of sodium oxide.

Norma-Jean [14]

Answer: 9.27 g of Na

Explanation:Please see attachment for explanation

7 0

3 years ago

33.56 g of fructose (C6H,206) and 18.88 g of water are mixed to obtain a 40.00 ml solution a. What is this solution's density? b

Darina [25.2K]

Explanation:

Mass of fructose = 33.56 g

Mass of water = 18.88 g

Total mass of the solution = Mass of fructose + Mass of water = M

M = 33.56 g + 18.88 g =52.44 g

Volume of the solution = V = 40.00 mL

Density = $\frac{Mass}{Volume}$

a) Density of the solution:

$\frac{M}{V}=\frac{52.44 g}{40.00 mL}=1.311 g/mL$

b) Molar mass of fructose = 180.16 g/mol

Moles of fructose = $n_1=\frac{ 33.56 g}{180.16 g/mol}=0.1863 mol$

Molar mass of water = 18.02 g/mol

Moles of water= $n_2=\frac{ 18.88 g}{18.02 g/mol}=1.0477 mol$

Mole fraction of fructose in this solution: $\chi_1$

$\chi_1=\frac{n_1}{n_1+n_2}=\frac{0.1863 mol}{0.1863 mol+1.0477 mol}$

$\chi_1=0.1510$

Mole fraction of water = $\chi_2=1-\chi_1=0.8490$

c) Average molar mass of of the solution:

= $\chi_1\times 180.16 g/mol+\chi_2\times 18.02 g/mol$

$=0.1510\times 180.16 g/mol+0.8490\times 18.02 g/mol=42.50 g/mol$

d) Mass of 1 mole of solution = 42.50 g/mol

Density of the solution = 1.311 g/mL

d) Specific molar volume of the solution:

$\frac{\text{Average molar mass}}{\text{Density of the mass}}$

$=\frac{42.50 g/mol}{1.311 g/mL}=32.42 mL/mol$

5 0

3 years ago

PLEASE HELP I DONT WANT TO FAIL!! ):

Fudgin [204]

Hope this helps :) I didn’t know how to write subscripts so I wrote it down on some paper.

3 0

3 years ago

If 287 mL of a 1.6 M glucose solution is diluted to 412 mL , what is the molarity of the diluted solution

satela [25.4K]

Answer:

The answer to your question is 1.11 M

Explanation:

Data

volume 1 = 287 ml

concentration 1 = 1.6 M

volume 2= 412 ml

concentration 2 = ?

Formula

Volume 1 x concentration 1 = Volume 2 x concentration 2

Solve for concentration 2

concentration 2 = (volume 1 x concentration 1) / volume 2

Substitution

concentration 2 = (287 x 1.6) / 412

Simplification

concentration 2 = 459.2 / 412

Result

concentration 2 = 1.11 M

5 0

3 years ago

When sulfur burns, it forms sulfur dioxide (SO2). Its chemical reaction is S + O2 → SO2.

Elenna [48]

Answer:

The mass of SO2 will be equal to the sum of the mass of S and O2.

Explanation:

This can be explained by the <em>Law of Conservation of Mass</em>. This law states that mass can neither be created nor destroyed. Knowing this, we can say that the reactants of a chemical reaction must be equal to the products.

In this case, the reactants Sulfur (S) and Oxygen (O2) must equal the mass of the product Sulfur Dioxide (SO2). Therefore, the statement <em>"The mass of SO2 will be equal to the sum of the mass of S and O2" </em>is correct.

4 0

3 years ago