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pantera1 [17]
3 years ago
10

Una pelota de tenis de 100 g de masa lleva una rapidez de 20 m/s. Al ser golpeada por una raqueta, se mueve en sentido contrario

con una rapidez de 40 m/s.
Calcular el impulso. Si le pelota permanece en contacto con la raqueta 〖10〗^(-2) sg, ¿Cuál es el módulo de la fuerza media del golpe?
Physics
1 answer:
REY [17]3 years ago
7 0

Answer:

Explanation:

El impulso aplicado a la pelota produce una variación en su momento lineal.

J = m (V -Vo)

Conviene elegir positivo el sentido de la velocidad final.

J = 0,100 kg [40 - (- 20)] m/s = 6 kg m/s

Saludos Herminio

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Explanation:

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4 years ago
Sodium chloride and calcium carbonate combine to form sodium carbonate and calcium chloride in the reversible reaction.
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Answer:

I think is Number 2

The rate at which calcium chloride is equal to the rate at which sodium chloride is produced.

Let me know if I'm wrong.

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Why does the moon cycle from new moon to full moon?
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It depends on where the sun is hitting the moon in relation to the earth
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The chart show the masses and velocities of two colliding objects that stick together after a collision.
finlep [7]

Answer:

<u><em></em></u>

  • <u><em>1,500 kg.m/s</em></u>

Explanation:

First, arrange the information in a table:

Object        Mass (kg)           Velocity (m/s)

  A                    200                      15

  B                     150                    - 10

After the collision, the two objects are stick together, thus you talk aobut one object and one momentum.

According to the law of convervation of momentum, the momentum after the collision is equal to the momentum before the collision.

<u>Momentum before the collision, P₁</u>:

          P_1=m_{A,1}\times v_{A,1}+m_{B,1}\times v_{B,1}

         P_1=200kg\times 15m/s+150kg\times (-10m/s)\\\\  P_1=3000kg.m/s-1500kg.m/s=1500kg.m/s

<u>Momentum after the collision</u>:

  • As stated, it es equal to the momentum before the collision: 1,500 kg . m/s
6 0
4 years ago
If rho(x,y) is the density of a wire (mass per unit length), then
lidiya [134]

Answer:

See description

Explanation:

With the given information we have:

x(t) = 1 + cos(t)\\ y(t)=sin(t)\\ \rho(x,y) = 3x

the interval is [0,\pi ]

now the mass m has the given expression:

m = \int \rho(x,y) dS

we will use the formula for a line integral and let:

dS=\sqrt{x'(t)^2 + y'(t)^2}=\sqrt{cos(t)^2 + sin(t)^2}dt=dt

therefore we have:

m=\int \rho(x,y)dS=\int\limits^\pi_0 {3*x}dS=\int\limits^\pi _0{3*(1+cos(t))dS\\=\int\limits^\pi _0{3*(1+cos(t))dt

we solve the integral:

m=3*\int\limits^\pi _0{(1+cos(t))dt= 3*(t+sin(t))\limits^\pi _0=3*\pi=9.42

7 0
3 years ago
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