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2 years ago

How do you balance Sb+I2=SbI3 show work please

Chemistry

1 answer:

egoroff_w [7]2 years ago

7 0

Answer:

2Sb + 3I₂ → 2SbI₃

Explanation:

The reaction expression we need to balance is:

Sb + I₂ → SbI₃

To balance this expression, we need to assign the variables a,b and c to each specie as the coefficient that will balance the expression.

aSb + bI₂ → cSbI₃

Conserving Sb : a = c

I : 2b = 3c

let a = 1, c = 1, b = $\frac{3}{2}$

Multiply through by 2;

a = 2, b = 3 and c = 2

2Sb + 3I₂ → 2SbI₃

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2 years ago

If the solubility of a gas is 10.5 g/L at 525 kPa pressure, what is the solubility of the gas when the pressure is 225 kPa? Show

Talja [164]

Answer:

4.5 g/L.

Explanation:

To solve this problem, we must mention Henry's law.

Henry's law states that at a constant temperature, the amount of a given gas dissolved in a given type and volume of liquid is directly proportional to the partial pressure of that gas in equilibrium with that liquid.

It can be expressed as: P = KS,

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S is the solubility of the gas.

At two different pressures, we have two different solubilities of the gas.

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P₁ = 525.0 kPa & S₁ = 10.5 g/L.

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3 years ago

How many Joules are released to cool 250.0 grams of liquid water from 100°C to 0°C? The specific heat of water is 4.180 J/g.C.

nlexa [21]

$\bold{\huge{\orange{\underline{ Solution}}}}$

$\bold{\underline{ Given :- }}$

We have 250g of liquid water and it needs to be cool at temperature from 100° C to 0° C
Specific heat of water is 4.180J/g°C

$\bold{\underline{ To \: Find :- }}$

We have to find the total number of joules released.

$\bold{\underline{ Let's \:Begin:- }}$

We know that,

Amount of heat energy = mass * specific heat * change in temperature

That is, 

$\sf{\red{ Q = mcΔT }}$

Subsitute the required values in the above formula :-

$\sf{ Q = 250 × 4.180 ×(0 - 100 )}$

$\sf{ Q = 250 × 4.180 × - 100 }$

$\sf{ Q = 250 × - 418}$

$\sf{\pink{ Q = - 104,500 J }}$

Hence, 104,500 J of heat is released to cool 250 grams of liquid water from 100° C to 0° C.

$\bold{\underline{ Now :- }}$

We have to tell whether the above process is endothermic or exothermic :-

Here, In the above process ΔT is negative and as a result of it Q is also negative that means above process is Exothermic

Exothermic process :- It is the process in which heat is evolved .
Endothermic process :- It is the process in which heat is absorbed .

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1 year ago