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Andrews [41]
3 years ago
12

MATH EASY PLEASE PLEASE HELP ME

Mathematics
1 answer:
BaLLatris [955]3 years ago
3 0

Answer:

D

Step-by-step explanation:

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the combined area of two squares is 45 square centimetres each side is twice as long as a side of the other square what length o
Ostrovityanka [42]

Answer:

Let the side of  one square be x.    Area = x*x = x²

Then the side of other square  would be 2x ,   Area = 2x*2x = 4x²

Combined area = x² + 4x²  = 5x²

This combined area = 45 cm²

you simplify

Therefore  5x²  = 45   Divide both sides by 5

                 x²  =  45/5

                 x²  = 9        Take square root of both sides

                 x   =  √9

                 x  = 3

Length of larger square is 2x  = 2*3 = 6 cm

Length of larger square = 6cm

Step-by-step explanation:

4 0
3 years ago
PLEASE HELP!
leva [86]

Answer:

B. 56°

Step-by-step explanation:

We are given that m∠R is 66° and m∠T is 122°.

We can apply the supplementary rule since ∠S and ∠T are a linear pair. So, we can use ∠T to find ∠S through 180° - 122° = 58°.

Now, we can use ∠R and ∠S to find ∠Q.

66° + 58° = 124°

180° - 124° = 56°

8 0
3 years ago
Evaluate the expression when m=-6.<br> 2<br> m + 5m - 4
Brums [2.3K]

Answer:

2

Step-by-step explanation:

m^2 + 5m - 4

Let m = -6

( -6) ^2 + 5(-6) -4

Exponents first

36 + 5(-6) -4

Then multiply

36 -30 -4

Then subtract

6 -4

2

5 0
3 years ago
please help me :( I need help
slava [35]

Answer:

Step-by-step explanation:

Lines l and m are the parallel lines and 't' is a transversal line,

Therefore, ∠1 ≅ ∠5 [Corresponding angle postulate]

∠5 ≅ ∠7 [Vertical angles theorem]

∠1 ≅ ∠7 [Transitive property]

Therefore, ∠1 ≅ ∠7 [Alternate exterior angles theorem]

4 0
3 years ago
If tn = 4n+1, find t1, t2, t3, and tn+1. Express tn+1−tn in its simplest form.
Doss [256]

Answer:

t_1=5

t_2=9

t_3=13

t_{n+1}-t_n=4

Step-by-step explanation:

We have that:

t_n=4n+1

When we substitute n=1, we get:

t_1=4*1+1=5

When we substitute n=2 we get:

t_2=4*2+1=9

When we substitute n=3, we get:

t_3=4*3+1=13

When we substitute n=n+1, we get:

t_{n+1}=4*(n+1)+1=4n+5

Now

t_{n+1}-t_n=4n+5-(4n+1)

We expand and simplify to obtain:

t_{n+1}-t_n=4n+5-4n-1

t_{n+1}-t_n=4

3 0
3 years ago
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