Answer:
The answer is 1.87nm/s.
Explanation:
The
water loss must be replaced by
of sap. 110g of sap corresponds to a volume of

thus rate of sap replacement is

The volume of sap in the vessel of length
is
,
where
is the cross sectional area of the vessel.
For 2000 such vessels, the volume is

taking the derivative of both sides we get:

on the left-hand-side
is the velocity
of the sap, and on right-hand-side
; therefore,

and since the cross-sectional area is
;
therefore,

solving for
we get:


which is the upward speed of the sap in each vessel.
The magnitude of the electric field for 60 cm is 6.49 × 10^5 N/C
R(radius of the solid sphere)=(60cm)( 1m /100cm)=0.6m

Since the Gaussian sphere of radius r>R encloses all the charge of the sphere similar to the situation in part (c), we can use Equation (6) to find the magnitude of the electric field:

Substitute numerical values:

The spherical Gaussian surface is chosen so that it is concentric with the charge distribution.
As an example, consider a charged spherical shell S of negligible thickness, with a uniformly distributed charge Q and radius R. We can use Gauss's law to find the magnitude of the resultant electric field E at a distance r from the center of the charged shell. It is immediately apparent that for a spherical Gaussian surface of radius r < R the enclosed charge is zero: hence the net flux is zero and the magnitude of the electric field on the Gaussian surface is also 0 (by letting QA = 0 in Gauss's law, where QA is the charge enclosed by the Gaussian surface).
Learn more about Gaussian sphere here:
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50/200×100%=25% is answer the formula is usefull energy output divided by total energy provided into 100%
It would be funny because . I will not be good