Which is a part of fitness will help improve your overall health?

Physics

2 answers:

Ipatiy [6.2K]3 years ago

5 0

Answer:

I'm not sure I think it is Muscular Endurance

Explanation:

I searched I on google.

Radda [10]3 years ago

3 0

Answer: I assume it would be aerobic endurance

Explanation:

If you have good aerobic endurance you are fit and can efficiently supply oxygen and nutrients to your muscles.

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¿Una persona de 60 corriendo a 4 m/s, tiene más energía cinética que un proyectil de 10 gramos a 300 m/s?

Svet_ta [14]

Explanation:

The question says that "Does a 60 kg person running at 4 m/s have more kinetic energy than a 10 gram projectile at 300 m/s ? "

Speed of a person is 4 m/s

Mass of a person is 60 kg

Kinetic energy of a person is : $K=\dfrac{1}{2}mv^2$

So,

$K=\dfrac{1}{2}\times 60\times 4^2\\\\K=480\ J$

Mass of a projectile is 10 grams or 0.01 kg

Speed of a projectile is 300 m/s

Kinetic energy of a projectile is :

$K=\dfrac{1}{2}mv^2$

$K=\dfrac{1}{2}\times 0.01\times (300)^2\\\\K=450\ J$

So, it is clear that the kinetic energy of a person is more than that of the kinetic energy of a projectile.

8 0

3 years ago

What is the acceleration of a body moving with uniform velocity?

AfilCa [17]

Acceleration is the rate of change of velocity, a body moving with uniform velocity does not possess acceleration at all i.e. acceleration is zero

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3 years ago

A particle of mass 3m is located 1.00 m from a particle of mass m. (a) Where should you put a third mass M so that the net gravi

Airida [17]

Explanation:

It is given that net gravitational force on M is exactly equal to zero. Hence, distance to M from the bigger mass is 3m. Therefore, expression for net force will be as follows.

$F_{net} = F_{1} + F_{2} = 0$

So,

$\frac{-G(3m)(M)}{x^{2}} + \frac{G(m)(M)}{(1 - x)^{2}} = 0$

The first term is negative as the third mass is located between the other two masses. This means that 3 m will be pulling it leftwards (negative x direction) and m will be pulling it rightwards (positive x direction).

$\frac{G(m)(M)}{(1 - x)^{2}} = \frac{G(3m)(M)}{(x)^{2}}$