Can Intrusive and Extrusive Igneous rocks form from the same mineral composition?

The equation for another reaction used in industry isCO(g) + H₂O(g) <img src="https://tex.z-dn.net/?f=%5Crightleftharpoons" id="

Sloan [31]

Answer:

(i) CO = 0.4 mol; H₂O = 1.6 mol; Kc = 4

(ii) CO = 0.67 mol; H₂O = 0.67 mol; CO₂ = 1.33 mol; H₂ = 1.33 mol

Explanation:

(i) For the equation given let's make a table of the concentrations for equilibrium (the volume is constant, so, we can do it with moles number)

CO(g) + H₂O(g) ⇄ H₂(g) + CO₂(g)

2.0 mol 3.2 mol 0 0 Initial

-x -x +x +x Reacts (stoichiometry is 1: 1: 1: 1)

2.0-x 3.2-x x x Equilibrium

In the equilibrum, the moles number of hydrogen and carbon dioxide are 1.6 mol, so x = 1.6 mol

The amounts of CO and H₂O are:

CO = 2.0 - 1.6 = 0.4 mol

H₂O = 3.2 - 1.6 = 1.6 mol

The constant of the equilibrium is the multiplications of the concentrations of products divided by the multiplication of the concentration of the reactants (all the concentrations elevated to the coefficient). So:

Kc = (1.6x1.6)/(0.4x1.6)

Kc = 1.6/0.4

Kc = 4

(ii) Kc must remais constant (it only changes with the temperature), so let's construct a new table of equilibrium:

CO(g) + H₂O(g) ⇄ H₂(g) + CO₂(g)

2.0 mol 2.0 mol 0 0 Initial

-x -x +x +x Reacts (stoichiometry is 1: 1: 1: 1)

2.0-x 2.0-x x x Equilibrium

Kc = (x*x)/((2.0-x)*(2.0-x))

4 = x²/(4 - 4x + x²)

16 - 16x + 4x² = x²

3x² - 16x + 16 = 0

Using Baskhara's equation:

Δ =(-16)² - 4x3x16

Δ = 256 - 192

Δ = 64

x = (-(-16) +/- √64)/(2*3)

x' = (16 + 8)/6 = 4

x'' = (16 - 8)/6 = 1.33

x must be small than 2.0, so x = 1.33 mol, which is the amount of hydrogen and carbon dioxide at equilibrium. The both reactants has 2.0 - 1.33 = 0.67 mol at equilibrium.

5 0

3 years ago

Traspasa el aire todo hasta llegar a la más alta esfera, y oye allí otro modo de no perecedera música, que es la fuente y la pri

kakasveta [241]

No entiendo cual es tu pregunta?

3 0

3 years ago

A 8.06 g piece of solid CO 2 is allowed to sublime in a balloon. The final volume of the balloon is 1.00 L at 300.0 K. What is t

natka813 [3]

Answer:

The pressure of the gas is 4.428 atm.

Explanation:

Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.

Considering a certain amount of ideal gas confined in a container where the pressure, volume and temperature can vary, but keeping the mass constant, that is, without altering the number of moles, the pressure, P, the temperature can be related, T and the volume, V, of an ideal gas using the ideal gas law:

P*V = n*R*T

where R is the ideal gas constant, and n is the number of moles of the gas.

In this case, to know n you must know the molar mass of the CO₂ compound. Being:

C: 12 g/mole
O: 16 g/mole

then, the molar mass of CO₂ is: 12 g/mole + 2*16 g/mole= 44 g/mole

Then you apply a rule of three: if 44 grams of CO₂ are present in 1 mole, 8.06 grams in how many moles are they?

$moles of CO_{2} =\frac{8.06 grams*1 mole}{44 grams}$

moles of CO₂= 0.18 moles

Then, you know:

P: ?
V: 1 L
n: 0.18 moles

R= 0.082 $\frac{atm*L}{mol*K}$

T= 300 K

Replacing in the equation of the ideal gas law:

P* 1 L= 0.18 moles* 0.082 $\frac{atm*L}{mol*K}$ * 300 K

Solving:

$P=\frac{0.18 moles* 0.082 \frac{atm*L}{mol*K} *300 K}{1 L}$

P= 4.428 atm

The pressure of the gas is 4.428 atm.

3 0

3 years ago

Number of atoms in 2.56 moles of He

bazaltina [42]

<h3>Answer:</h3>

1.54 × 10²⁴ atoms He

<h3>General Formulas and Concepts:</h3>

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Chemistry

Atomic Structure

Moles
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

Using Dimensional Analysis

<h3>Explanation:</h3>

Step 1: Define

[Given] 2.56 moles He

[Solve] atoms He

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

[DA] Set up: $\displaystyle 2.56 \ mol \ He(\frac{6.022 \cdot 10^{23} \ atoms \ He}{1 \ mol \ He})$
[DA] Multiply [Cancel out units]: $\displaystyle 1.54163 \cdot 10^{24} \ atoms \ He$

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

1.54163 × 10²⁴ atoms He ≈ 1.54 × 10²⁴ atoms He

5 0

3 years ago

The solvolysis of t-butyl bromide in methanol yields 2-methylpropene in an E1 reaction (among other products). What is the effec

jolli1 [7]

Answer:

See explanation

Explanation:

For a reaction that proceeds by E1 mechanism, the rate determining step involves the formation of the carbocation.

The rate of formation of this carbocation depends only on the concentration of the t-butyl bromide since it is the only specie that enters into the rate equation.

Hence, when the concentration of t-butyl bromide is tripled, the rate of reaction is tripled.

Methanol does not enter into the rate equation hence doubling its concentration does not affect the rate of reaction.

7 0

3 years ago