The percentage of the sulfur (S) in the compound CuSO₄ is 20.1 %.
<h3>What is the mass percentage?</h3>
The percentage of an element in a compound can be determined as the number of parts by mass of that element present in 100 parts by mass of the given compound.
First, calculate the molecular mass of the given compound by the addition of the atomic masses of all the present elements in the molecular formula. Then, the percentage of the elements can be determined by dividing the total mass of the element by the molar mass of the compound multiplied by 100.
Given, the atomic mass of copper, sulfur, and oxygen is 63.55 g, 32.07 g, and 16.0g respectively.
The molecular mass of CuSO₄ = 63.55 + 32.07 + 4(16.0) = 159.62 g
The mass percentage of the sulphur = (32.07/159.62) × 100 = 20.1 %
Therefore, the mass percentage of the sulfur is equal to 20.1 %.
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The atomic number of an element is the same as the number of protons. As long as the atom is neutral, your electrons and protons will be the same number. To find neutrons, you subtract the atomic number from the mass number.
mass number - atomic number = number of neutrons
Answer:
6. this is because atomic mass 11 - atomic number 5 is equal to 6 neutrons.
Answer:
a) The molecule is always polar.
Explanation:
The molecule is always polar because of two reasons:
- all the bonds are polar due to the difference in electronegativity between carbon and hydrogen & carbon and chlorine.
AND IMPORTANTLY
- The molecule is asymmetrical meaning that the dipoles cannot cancel each other out (like they do in methane or carbon dioxide for example) so the net effect is a polar molecule.
