All categories

2 years ago

You pull a 200 kg box straight up with a rope connected to a helicopter. If the

Physics

2 answers:

Tanzania [10]2 years ago

5 0

Answer:

Acceleration of the box = 0.2 m / s²

Explanation:

Given:

Mass of box = 200 kg

Magnitude of the tension = 2,000 N

Find:

Acceleration of the box

Computation:

Ma = T - Mg

200(a) = 2,000 - (200)(9.8)

200(a) = 2,000 - 1960

200(a) = 40

a = 40 / 200

a = 0.2

Acceleration of the box = 0.2 m / s²

s344n2d4d5 [400]2 years ago

4 0

Answer:

The acceleration is 0.2 m/s^2.

Explanation:

Tension, T = 2000 N

mass, m = 200 kg

Let the acceleration is a.

So, by the use of Newton's second law

Net force = mass x acceleration

T - mg = ma

2000 - 200 x 9.8 = 200 x a

2000 - 1960 = 200 a

a = 0.2 m/s^2

You might be interested in

Suppose you throw a ball vertically upward with a speed of 49 m/s. Neglecting air friction, what would be the height of the ball

vlabodo [156]

Answer:

78.4 m

Explanation:

Using newton's equation of motion,

S = ut + 1/2gt²......................... Equation 1

Where S = Height, t = time, u = initial velocity, g = acceleration due to gravity.

Note: Taking upward to be negative, and down ward positive

Given: u = 49 m/s, t = 2.0 s, g = -9.8 m/s²

Substitute into equation 1

S = 49(2) - 1/2(9.8)(2)²

S = 98 - 19.6

S = 78.4 m

Hence the height of the ball two seconds later = 78.4 m

6 0

2 years ago

B. Projectile on cliff (range)

dimulka [17.4K]

Answer:

x = 41.28 m

Explanation:

This is a projectile launching exercise, let's find the time it takes to get to the base of the cliff.

Let's start by using trigonometry to find the initial velocity

cos 25 = v₀ₓ / v₀

sin 25 = Iv_{oy} / v₀

v₀ₓ = v₀ cos 25

v_{oy} = v₀ sin 25

v₀ₓ = 22 cos 25 = 19.94 m / s

v_{oy} = 22 sin 25 = 0.0192 m / s

let's use movement on the vertical axis

y = y₀ + v_{oy} t - ½ g t²

when reaching the base of the cliff y = 0 and the initial height is y₀ = 21 m

0 = 21 + 0.0192 t - ½ 9.81 t²

4.905 t² - 0.0192 t - 21 = 0

t² - 0.003914 t - 4.2813 =0

we solve the quadratic equation

t = $\frac{ 0.003914\ \pm \sqrt{0.003914^2 + 4 \ 4.2813 } }{2}$

t = $\frac{0.003914 \ \pm 4.13828}{2}$

t₁ = 2.07 s

t₂ = -2.067 s

since time must be a positive scalar quantity, the correct result is

t = 2.07 s

now we can look up the distance traveled

x = v₀ₓ t

x = 19.94 2.07

x = 41.28 m

5 0

2 years ago

What is the direction and speed of an object?

KatRina [158]

Answer:

Explanation:

Velocity by definition means speed and direction of an object. This means it has a value and a positive or minus sign indicating direction. Speed is the absolute value of velocity because there is no direction correlated with speed. If you add a direction, it is then called velocity

7 0

3 years ago

Reduce<br> Reflects<br> Transfers<br> Stops

Bond [772]

I think transfers is the answer

4 0

2 years ago

Which of the following is an example of an irregular meter? A. Four beats per measure B. Five beats per measure C. Two beats per

Komok [63]

B. 5 beats per measure.

7 0

2 years ago