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Serggg [28]
3 years ago
5

You pull a 200 kg box straight up with a rope connected to a helicopter. If the

Physics
2 answers:
Tanzania [10]3 years ago
5 0

Answer:

Acceleration of the box = 0.2 m / s²

Explanation:

Given:

Mass of box = 200 kg

Magnitude of the tension = 2,000 N

Find:

Acceleration of the box

Computation:

Ma = T - Mg

200(a) = 2,000 - (200)(9.8)

200(a) = 2,000 - 1960

200(a) = 40

a = 40 / 200

a = 0.2

Acceleration of the box = 0.2 m / s²

s344n2d4d5 [400]3 years ago
4 0

Answer:

The acceleration  is 0.2 m/s^2.

Explanation:

Tension, T = 2000 N

mass, m = 200 kg

Let the acceleration is a.

So, by the use of Newton's second law

Net force = mass x acceleration

T - mg = ma

2000 - 200 x 9.8 = 200 x a

2000 - 1960 = 200 a

a = 0.2 m/s^2

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What would the average speed in kph of a horse and rider be if they cover a total distance of 14 km in 249 minutes
romanna [79]

Average speed = (distance covered) / (time to cover the distance)

Average speed = (14 km) / (249 min)

Average speed = (14/249) (km/min)

Average speed = (14/249) (km/min) x (60 min/hr)

Average speed = (14 x 60 / 249) km/hr

<em>Average speed = 3.37 km/hr</em>

8 0
4 years ago
Primary colors of light?
brilliants [131]

The primary colors of light are:

1. Green

2. Red

3.Blue

4. Yellow

5. White

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5 0
4 years ago
Read 2 more answers
A man weighing 680N and a woman weighing 500N have the same momentum. What is the ratio of the man's kinetic energy Km to that o
svet-max [94.6K]

Answer:

\dfrac{K_m}{K_w}=0.734

Explanation:

given,

weight of the man = 680 N

weight of the woman = 500 N

mass of man = \dfrac{680}{9.8}

  M_m = 69.4 Kg

mass of woman

= \dfrac{500}{9.8}

M_w = 51 Kg

ratio of man's kinetic energy Km to that of the woman Kw

\dfrac{K_m}{K_w}=\dfrac{\dfrac{P_m^2}{2M_m}}{\dfrac{P_w^2}{2M_w}}

momentum is same

\dfrac{K_m}{K_w}=\dfrac{2M_w}{2M_m}

\dfrac{K_m}{K_w}=\dfrac{M_w}{M_m}

\dfrac{K_m}{K_w}=\dfrac{51}{69.4}

\dfrac{K_m}{K_w}=0.734

3 0
4 years ago
What is Newton’s 3rd Law of Motion?
sasho [114]

Answer:

His third law states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A. Notice that the forces are exerted on different objects.

Explanation:

5 0
3 years ago
A cylindrical bucket, open at the top, is 28.0 cm high and 11.0 cm in diameter. A circular hole with a cross-sectional area 1.55
svlad2 [7]

Answer:

so height is 0.1283 m

Explanation:

given data

height = 28 cm

diameter = 11 cm

cross-sectional area = 1.55 cm2

water flow rate  =  2.46×10^−4 m3/s

to find out

How high will the water in the bucket rise

solution

we know that here

potential energy = kinetic energy

mgh = 1/2 mv²

multiply both sides by the 2 and we get

2mgh=mv²

solve it we get

√(2gh) = v    ....................1

h = v²/2g   ...............2

and

flow rate = A V

2.46×10^−4 = V 1.55×10^−4

V = 1.5870 m/s

so from 2

h = v²/2g

h = 1.5870²/ 2(9.81)

h = 0.1283 m

so height is 0.1283 m

6 0
4 years ago
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