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3 years ago

You pull a 200 kg box straight up with a rope connected to a helicopter. If the

Physics

2 answers:

Tanzania [10]3 years ago

5 0

Answer:

Acceleration of the box = 0.2 m / s²

Explanation:

Given:

Mass of box = 200 kg

Magnitude of the tension = 2,000 N

Find:

Acceleration of the box

Computation:

Ma = T - Mg

200(a) = 2,000 - (200)(9.8)

200(a) = 2,000 - 1960

200(a) = 40

a = 40 / 200

a = 0.2

Acceleration of the box = 0.2 m / s²

s344n2d4d5 [400]3 years ago

4 0

Answer:

The acceleration is 0.2 m/s^2.

Explanation:

Tension, T = 2000 N

mass, m = 200 kg

Let the acceleration is a.

So, by the use of Newton's second law

Net force = mass x acceleration

T - mg = ma

2000 - 200 x 9.8 = 200 x a

2000 - 1960 = 200 a

a = 0.2 m/s^2

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John walks 1.00 km north, then turns right and walks 1.00 km east. His speed is 1.50 m/s during the entire stroll.a) What is the

avanturin [10]

Answer:

(a) 1.414 km

(b) 1.06 m/s

Explanation:

(a) For John:

Distance = 1 km north and then 1 km east

Speed = 1.5 m/s

total distance traveled = 1 + 1 = 2 km = 2000 m

Time taken to travel = Distance / speed

t = 2000 / 1.5 = 1333.3 seconds

Displacement = $\sqrt{1^{2}+1^{2}}=1.414 km$

(b) For jane :

Time is same as john = 1333.33 second

Distance = 1.414 km = 1414 m

Speed = distance / time = 1414 / 1333.33 = 1.06 m/s

3 0

3 years ago

3 a There is a thin layer of water between the blade and the ice. Suggest how this affects friction .

Gelneren [198K]

Answer:

The water acts like a lubricant therefore has a smooth motion over the ice.

8 0

2 years ago

Two 110 kg bumper cars are moving toward each other in opposite directions. Car A is moving at 8 m/s and Car Z at –10 m/s when t

julsineya [31]

This is a conservation of momentum problem! Here's how to do it:

6 0

3 years ago

The intensity I of light varies inversely as the square of the distance D from the source. If the intensity of illumination on a

emmasim [6.3K]

The intensity on a screen 20 ft from the light will be 0.125-foot candles.

<h3>What is the distance?</h3>

Distance is a numerical representation of the length between two objects or locations.

The intensity I of light varies inversely as the square of the distance D from the source;

I∝(1/D²)

The ratio of the intensity of the two cases;

$\rm \frac{I_1}{I_2} =(\frac{D_2}{D_1} )^2\\\\ \rm \frac{2}{I_2} =(\frac{20}{5} )^2\\\\ \frac{2}{I_2} =4^2 \\\\ I_2= \frac{2}{16} \\\\ I_2= 0.125 \ foot-candles$

Hence, the intensity on a screen 20 ft from the light will be 0.125 foot-candles

To learn more about the distance refer to the link;

brainly.com/question/26711747

#SPJ1

6 0

2 years ago

Who water rocket starts from rest and roses straight up with an acceleration of 5 m/s until it runs out of water 2.5 seconds lat

Kitty [74]

Answer:

23. 4375 m

Explanation:

There are two parts of the rocket's motion

1 ) accelerating (assume it goes upto h1 height )

using motion equations upwards

$s = ut+\frac{1}{2}*a*t^{2} \\h_1=0+\frac{1}{2}*5*2.5^{2} \\=15.625 m$

Lets find the velocity after 2.5 seconds (V1)

V = U +at

V1 = 0 +5*2.5 = 12.5 m/s

2) motion under gravity (assume it goes upto h2 height )

now there no acceleration from the rocket. it is now subjected to the gravity

using motion equations upwards (assuming g= 10m/s² downwards)

V²= U² +2as

0 = 12.5²+2*(-10)*h2

h2 = 7.8125 m

maximum height = h1 + h2

= 15.625 + 7.8125

= 23. 4375 m

3 0

3 years ago