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3 years ago

Factor 64x² + 114x + 81

Mathematics

1 answer:

slavikrds [6]3 years ago

3 0

The answer is 64x^2+114x+81. Hope this helps.

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Please help asap :)

Nat2105 [25]

Your answer would be 2x^2=4x

also I have a question I need help with, would you mind?

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3 years ago

Write each expression as an algebraic (nontrigonometric) expression in u, u > 0.

max2010maxim [7]

Answer:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

Step-by-step explanation:

We want to write the trignometric expression:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0$

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

$\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)$

Take the secant of both sides:

$\displaystyle \sec(\theta)=\frac{u}{10}$

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

$\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}$

By substitutition:

$\displaystyle= \sin(2\theta)$

Using an double-angle identity:

$=2\sin(\theta)\cos(\theta)$

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

$\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)$

Simplify. Therefore:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

4 0

3 years ago

What percent of the ninth grade students scored between 78 and 96?

kiruha [24]

Answer:

30%

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Which of the following describes the diagonals of a square?

Feliz [49]

Answer:

ALL OF THE ANSWERS ARE CORRECT .

HOPE IT HELP YOU.

5 0

3 years ago

Is (-a + b)² = a² - 2ab + b² right or wrong, and why?

antiseptic1488 [7]

Answer:

$\huge\boxed{\sf Right.}$

Step-by-step explanation:

$(-a+b)^2$

Let's apply the formula (x+y)² = x² + 2xy + y²

Here, x = -a and y = b

So,

= (-a)² + 2(-a)(b) + (b)²

= a² - 2ab + b²

Hence, it has been proved that (-a + b)² = a² - 2ab + b².

$\rule[225]{225}{2}$

Hope this helped!

6 0

3 years ago