Answer:1. ![AlBr_3](https://tex.z-dn.net/?f=AlBr_3)
2.
3.![N_2O_5](https://tex.z-dn.net/?f=N_2O_5)
4. ![K_2Cr_2O_7](https://tex.z-dn.net/?f=K_2Cr_2O_7)
5.
Explanation:
Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.
Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.
1.
has empirical formula of
2.
has empirical formula of ![NaSO_2](https://tex.z-dn.net/?f=NaSO_2)
3.
has empirical formula of
4.
has empirical formula of
5.
has empirical formula of
Answer:
The mass of solution will be "395.78 g".
Explanation:
Given:
Mass of acetic acid,
= 30 g
Percentage,
= 7.58% w/w
Now,
⇒ % ![=\frac{Mass \ of \ acetic \ acid}{Mass \ of \ solution}\times 100](https://tex.z-dn.net/?f=%3D%5Cfrac%7BMass%20%5C%20of%20%5C%20acetic%20%5C%20acid%7D%7BMass%20%5C%20of%20%5C%20solution%7D%5Ctimes%20100)
By putting the values, we get
⇒ ![7.58=\frac{30}{Mass \ of \ solution}\times 100](https://tex.z-dn.net/?f=7.58%3D%5Cfrac%7B30%7D%7BMass%20%5C%20of%20%5C%20solution%7D%5Ctimes%20100)
⇒ ![Mass \ of \ solution=\frac{30\times 100}{7.58}](https://tex.z-dn.net/?f=Mass%20%5C%20of%20%5C%20solution%3D%5Cfrac%7B30%5Ctimes%20100%7D%7B7.58%7D)
⇒ ![=\frac{3000}{7.58}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B3000%7D%7B7.58%7D)
⇒
Answer: yo yo dog i need points
Explanation:
fr fr
Answer: Both fluorescence and phosphorescence are based on the ability of a substance to absorb light and emit light of a longer wavelength and therefore lower energy. The main difference is the time in which it takes to do so. So if it disappears immediately, it's fluorescence. If it lingers, it's phosphorescence.
Explanation:
C. Decreasing the temperature
D. Raising the pressure
<h3>Further explanation</h3>
Given
Reaction
2SO₂+O₂⇔2SO₃+energy
Required
Changes to the formation of products
Solution
The formation of SO₃ is an exothermic reaction (releases heat)
If the system temperature is raised, then the equilibrium reaction will reduce the temperature by shifting the reaction in the direction that requires heat (endotherms). Conversely, if the temperature is lowered, then the equilibrium shifts to a reaction that releases heat (exothermic)
While on the change in pressure, then the addition of pressure, the reaction will shift towards a smaller reaction coefficient
in the above reaction: the number of coefficients on the left is 3 (2 + 1) while the right is 2
As the temperature decreases, the equilibrium will shift towards the exothermic reaction, so the reaction shifts to the right towards SO₃( products-favored)
And increasing the pressure, then the reaction shifts to the right SO₃( products-favored)⇒the number of coefficients is greater