You cant solve for x or y
9514 1404 393
Answer:
{-8, -4, -2, -1, 1, 2, 4, 8}
Step-by-step explanation:
Possible rational roots are positive and negative divisors of the constant 8:
{-8, -4, -2, -1, 1, 2, 4, 8}
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<em>Additional comment</em>
This polynomial has no rational roots. Its two real roots are both negative and irrational.
first term = initial number
second term = initial number + common difference
third term = initial number + 2(common difference)
So...
2x+5-(x+4) = common difference
4x+3-(2x+5) = also common difference
2x+5-(x+4) = x+1
4x+3-(2x+5) = 2x-2
Because x+1=2x-2 we can solve for x.
x=3
So the sequence goes... 7,11,15...
19 is the fourth term
Answer:
The hundredths place
Expanation
6 is in the one's place
2 is in the theth's place
1 is in the hundredth's place
3 is in the thousandth's place
