Answer:
9 grams
Explanation:
Hope it can help you.....
Answer:
88%.
Explanation:
The percentage yield of lead sulfate in this experiment is 88% if 2.53 is divided by 2.85 and multiply by 100. The percentage yield can be calculated when the experimental yield is divided by theoretical yield and then multiply by 100. The percentage yield tells us about the actual yield that is gained in the end of experiment which is lower than theoretical yield.
Answer:
127.15 g of ZnCl₂
Solution:
The balance chemical equation is as follow,
<span> Zn + 2 HCl </span>→ ZnCl₂ + H₂
According to equation,
65.38 g (1 mole) of Zn produced = 136.28 g (1 mole) of ZnCl₂
So,
61.0 g of Zn will produce = X g of ZnCl₂
Solving for X,
X = (61.0 g × 136.28 g) ÷ 65.38 g
X = 127.15 g of ZnCl₂
Explanation:
de Broglie wavelength= h/mv
v=h/m x de Broglie wavelength
v= (6.626× 10^-34)/ (2347× 1.27 × 10^-38)
v= 22.229 m/s(according to Google scientific calculator)
am sorry I don't hv a calculator at hand
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