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Alja [10]
3 years ago
11

The higher the voltage across a bulb the b__________ it is.

Physics
2 answers:
podryga [215]3 years ago
8 0

Answer:

Brighter

Explanation:

Sonja [21]3 years ago
7 0
The higher the voltage across à bulbe the brighter it is.
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Using the graph above, explain what happened on the amount carbon in the atmosphere 1960 to 2020.
Ivenika [448]

Answer:

No graph...

Explanation:

4 0
3 years ago
A speaker vibrates at a frequency of 200 hz. What is it's period ?
Katen [24]
200 Hz = 200 cycles per sec 

<span>1 cycle, the period = 1/200 = 0.005 seconds, or 5 milli seconds.</span>
8 0
3 years ago
What best describes hooke’s equation?
NeX [460]
The spring balance
F =ke
6 0
3 years ago
you ride a bike for 2 hours at 25 km/hr then 3 hours at 34 km/hr. what is your average velocity (in km/hr)?
mamaluj [8]
<h3>Answer:</h3>

30.4 km/hr

<h3>Explanation:</h3>

<u>We are given</u>;

  • Speed in the first 2 hours as 25 km/hr
  • Speed in the next 3 hours as 34 km/hr

We are required to determine the average velocity in km/hr

  • To get the average velocity we divide total distance by total time.
  • Thus, we need to determine the total distance

Distance = Speed × time

Distance covered in the first 2 hours;

               = 25 km/hr × 2 hours

               = 50 km

Distance in the next 3 hours

                = 34 km/hr × 3 hours

                = 102 km

Therefore, total distance = 50 km + 102 km

                                        = 152 km

Total time = 2 hrs + 3 hrs

                = 5 hours

Therefore;

Average speed = 152 km ÷ 5 hours

                          = 30.4 km/hr

Thus, the average speed is 30.4 km/hr

4 0
3 years ago
Toby's Trucking Company determined that on an annual basis, the distance traveled per truck is normally distributed, with a mean
Reptile [31]

Answer: 56994 miles

Explanation:

Given : Toby's Trucking Company determined that on an annual basis, the distance traveled per truck is normally distributed with

\mu=50,000\text{ miles}

Standard deviation : \sigma=12,000\text{ miles}

Let a be the distance traveled by at least 72% of the trucks.

Let X be the random variable that represents the distance traveled by a truck

Then P(x\geq a)=0.72

The critical value corresponds to p-value 0.72 :z=0.5828415

Also, z=\dfrac{x-\mu}{\sigma}

\Rightarrow\ 0.5828415=\dfrac{a-50000}{12000}\\\\\Rightarrow\ a=12000(0.5828415)+50000=56994.098\approx56994

Hence, 56994 miles will be traveled by at least (equal to and more than) 72% of the trucks .

6 0
3 years ago
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