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Elena-2011 [213]
3 years ago
9

Hhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

Chemistry
1 answer:
n200080 [17]3 years ago
5 0

Answer:

Explanation:

Hhhhhhhhhhhhhhhhhhhhh

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What quantum number of the hydrogen atom comes closest to giving a 24-nm-diameter electron orbit?
Paraphin [41]

<em>n</em> = 15. A Bohr orbit with <em>n</em> = 15 comes closest to having a 24 nm diameter .

The formula for the radius <em>r</em> of the <em>n</em>th orbital of a hydrogen atom is

<em>r</em> = <em>n</em>^2·<em>a</em>

where

<em>a</em> = the Bohr radius = 0.0529 nm

We can solve this equation to get

<em>n</em> = √ (<em>r</em>/<em>a</em>)

If <em>d</em> = 24 nm, <em>r</em> = 12 nm.

∴ <em>n</em> = √(12 nm/0.0529 nm) = √227 = 15.1

<em>n</em> must be an integer, so <em>n</em> = 15.

4 0
3 years ago
Without looking at the periodic table, identify the group, period, and
kobusy [5.1K]

the group : 2

periode : 6

block = 2

atomic number = 56

<h3>Further explanation </h3>

We can divide the periodic system into several parts:

1. Block s: groups 1 and 2 (having a configuration of 1s-7s) consist of active metals except for H (non-metals) and He (noble gases)

2. Block p: group 13-18 (has a 2p-6p configuration), also called a representative element because it includes metals, non-metals and metalloids

3. Block d: group 3-12 (having the 3d-6d configuration), are transition metal elements

4. Block f: Lanthanides and Actinides (having a 4f-5f configuration), are inner transition elements that are also metal

The element with the electron configuration :  [Xe]6s²

The outer shell 6s² :

Electron configuration :

1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s², 4d¹⁰, 5p⁶, 6s² : electron =56

group⇒valence electron ⇒2

period⇒the greatest value of the quantum number n⇒6

The element that is in period 6, and belongs to group 2 and has the atomic number 56 and in the block s

4 0
3 years ago
You add 10.0 grams of solid copper(II) phosphate, Cu3(PO4)2, to a beaker and then add 100.0 mL of water to the beaker at T = 298
Natalija [7]

Answer:

1.4×10-37

Explanation:

The equation for the dissolution of the copper II phosphate is first written as shown and the ICE table is set up as also shown. S is obtained as shown and this is now used to obtain 2s and subsequently the solubility product of the calcium phosphate as shown in detail in the image attached to this solution. The step-by-step solution shows how to obtain Ksp when concentration at equilibrium is given.

3 0
4 years ago
What is The element in group 4 and period 3.
Rina8888 [55]

Explanation:

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6 0
3 years ago
|A titanium ore contains rutile (TiO2) plus some oxides of iron and silica. When it is heated with
USPshnik [31]

Explanation:

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4 0
3 years ago
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