A large number in front of a compound designates how many units there are of that compound. Parentheses can be used to designate a special structure, where other molecules are attached to the larger, complex molecule.
The answer is unrestrained hair.
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The answer is 4.0 moles of magnesium
because...
..
...4.0mol Makmol O2 =3.0mol O2
Answer:
a) Same
b) Nitrogen
c) Same
d) Nitrogen
Explanation:
a)
The formula for partial pressure of a gas is equal to
Here nB is the number of moles .
The number of moles for both the gases are same and hence the partial pressure for the two gases will also be same.
b) The greater average velocity is calculated by using following formula
Here M is the molar mass.
Molar mass of nitrogen is greater than the molar mass of xenon and hence nitrogen will have higher greater average velocity
c) As we know, the average kinetic energy of gas particles is dependent on the absolute temperature of gas and if all the gases are at same temperature, their kinetic energy will also be same. Since nitrogen and xenon are at same temperature, their kinetic energy will be same
d) Effusivity is depended directly on the thermal conductivity, density and and the specific heat capacity.
All these three parameters are higher in case of nitrogen. Thus, it will effuse first
Answer:
1.48 M
Explanation:
Step 1:
The balanced equation for the reaction. This is given below:
Mg + H2SO4 —> MgSO4 + H2
Step 2:
Determination of the number of mole of Mg in 80.0 mL of 0.200 M Mg solution. This is illustrated below:
Molarity of Mg = 0.200 M
Volume of solution = 80 mL = 80/1000 = 0.08L
Mole of Mg =?
Molarity = mole /Volume
0.2 = mole /0.08
Mole = 0.2 x 0.08
Mole of Mg = 0.016 mole.
Step 3:
Determination of the number of mole of H2SO4 that reacted. This is illustrated below:
Mg + H2SO4 —> MgSO4 + H2
From the balanced equation above,
1 mole of Mg reacted with 1 mole of H2SO4.
Therefore, 0.016 mole of Mg will also react with 0.016 mole of H2SO4.
Step 4:
Determination of the concentration of the acid.
Mole of H2SO4 = 0.016 mole.
Volume of acid solution = 10.8 mL = 10.8/1000 = 0.0108 L
Molarity =?
Molarity = mole /Volume
Molarity = 0.016/0.0108
Molarity of the acid = 1.48 M
Therefore, the concentration of acid is 1.48 M
