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garik1379 [7]
3 years ago
7

Substance that are _________ are unable to be mixed together.

Chemistry
1 answer:
Elza [17]3 years ago
8 0

Answer:

Immiscible

Explanation:

Not sure what kind of substance but this is form liquids.

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If the element is closer to the top of the table is it's ionization energy larger?
Ulleksa [173]

Answer:

21

Explanation:

3 0
3 years ago
A sample of iron metal is placed in a graduated cylinder. it is noted that 10.4 ml of water is displaced by the iron. the iron i
Pavel [41]
<h3>Answer:</h3>

                 162.43 g of FeCl₂

<h3>Explanation:</h3>

Step 1: Calculate mass of Fe;

As,

                                   Density  =  Mass ÷ Volume

Or,

                                   Mass  =  Density × Volume

Where Volume is the volume of water displaced  =  10.4 mL

Putting values,

                                   Mass  =  7.86 g.mL⁻¹ × 10.4 mL

                                   Mass  =  81.744 g of Fe

Step 2: Calculate amount of FeCl₂;

The balance chemical equation is as follow,

                                Fe  +  2 HCl   →    FeCl₂  +  H₂ ↑

According to this equation,

       55.85 g (1 mol) Fe produced  =  110.98 g (1 mol) of FeCl₂

So,

               81.744 g Fe will produce  =  X g of FeCl₂

Solving for X,

                    X  =  (81.744 g × 110.98 g) ÷ 55.85 g

                     X =  162.43 g of FeCl₂

7 0
3 years ago
Can you help me plz I think it’s b or c
Anettt [7]

i think its C pls dont get mad if it is wrong

4 0
3 years ago
Read 2 more answers
In a neutralization reaction, 24.6 mL of 0.300 M H2SO4(aq) reacts completely with 20.0 mL of NaOH(aq). The products are Na2SO4(a
stiv31 [10]

Answer : The concentration of the NaOH solution is, 0.738 M

Explanation :

To calculate the concentration of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=0.300M\\V_1=24.6mL\\n_2=1\\M_2=?\\V_2=20.0mL

Putting values in above equation, we get:

2\times 0.300M\times 24.6mL=1\times M_2\times 20.0mL

M_2=0.738M

Thus, the concentration of the NaOH solution is, 0.738 M

7 0
3 years ago
suffixes Refer to the word parts table that you made for the words in Section 2 containing the suffix -ic. Use each of the words
Sladkaya [172]

Explanation:

need an image

3 0
3 years ago
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