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garik1379 [7]
2 years ago
7

Substance that are _________ are unable to be mixed together.

Chemistry
1 answer:
Elza [17]2 years ago
8 0

Answer:

Immiscible

Explanation:

Not sure what kind of substance but this is form liquids.

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Bromine can be classified as a
sergiy2304 [10]

Answer:

Halogen / salt-former

Explanation:

Bromine is classified as an element in the 'Halogens' section which can be located in group 7 of the Periodic Table. The term "halogen" means "salt-former" and compounds containing halogens are called "salts".

8 0
3 years ago
Imagine you are given a mystery element. It is, however, a discovered and known element. You may perform a maximum of two observ
miv72 [106K]

The classification of it being a metal, nonmetal, or metalliod will be useful in the process of elimination to determine what it is. Then for the second test, meauring the atomin radius will narrow it down quicker to the mystery elemet's name.

Since you determined what part of the periodic table it's on, then when measuring the atomic radius, you should be able to pinpoint what the element is more surely.

6 0
2 years ago
Read 2 more answers
The boiling point of bromine is 59 °C. Which of the following best predicts the boiling point of iodine monochloride, a polar co
soldier1979 [14.2K]

Answer:

Higher than 59 °C because dipole-dipole interactions in iodine monochloride are stronger than dispersion forces in bromine.

Explanation:

I just took the test and i got it right

6 0
3 years ago
Read 2 more answers
A natural charge by an atom is caused by which of the following conditions?
Lera25 [3.4K]

Answer:

C

Explanation:

I'm assuming that you meant to type neutral charge.

Since electrons are negative and protons are positive, having a balanced number of both of these would cause an atom to have a neutral charge.

5 0
2 years ago
Calculate the volume of 0.684mol of carbon dioxide at s.t.p. show working
solong [7]

Answer: The volume of 0.684 mol of carbon dioxide at s.t.p. is 15.3 L

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 1 atm (at STP)

V = Volume of gas = ?

n = number of moles = 0.684

R = gas constant = 0.0821Latm/Kmol

T =temperature =273K   (at STP)

V=\frac{nRT}{P}

V=\frac{0.684\times 0.0821L atm/K mol\times 273K}{1atm}

V=15.3L

Thus the volume of 0.684 mol of carbon dioxide at s.t.p. is 15.3 L

6 0
3 years ago
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