Mass of KCl= 19.57 g
<h3>Further explanation</h3>
Given
12.6 g of Oxygen
Required
mass of KCl
Solution
Reaction
2KClO3 ⇒ 2KCl + 3O2
mol O2 :
= mass : MW
= 12.6 : 32 g/mol
= 0.39375
From the equation, mol KCl :
= 2/3 x mol O2
= 2/3 x 0.39375
=0.2625
Mass KCl :
= mol x MW
= 0.2625 x 74,5513 g/mol
= 19.57 g
Answer:
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Explanation:
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<u>Answer:</u> The final volume of the oxygen gas is 4.04 L
<u>Explanation:</u>
To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.
Mathematically,
where,
are the initial volume and temperature of the gas.
are the final volume and temperature of the gas.
We are given:
Putting values in above equation, we get:
Hence, the final volume of the oxygen gas is 4.04 L
Answer:
1.2* 10³ rNe.
Explanation:
Given speed of neon=350 m/s
Un-certainity in speed= (0.01/100) *350 =0.035 m/s
As per heisenberg uncertainity principle
Δx*mΔv ≥\frac{h}{4\pi }
4π
h
..................(1)
mass of neon atom =\frac{20*10^{-3} }{6.22*10^{-23} } =3.35*10^{-26} kg
6.22∗10
−23
20∗10
−3
=3.35∗10
−26
kg
substituating the values in eq. (1)
Δx =4.49*10^{-8}10
−8
m
In terms of rNe i.e 38 pm= 38*10^{-12}10
−12
Δx=\frac{4.49*10^{-8} }{38*10^{-12} }
38∗10
−12
4.49∗10
−8
=0.118*10^{4}10
4
* (rNe)
=1.18*10³ rN
= 1.2* 10³ rNe.
Explanation:
This is the answer
