Answer:
A) The speed of the water must be 8.30 m/s.
B) Total kinetic energy created by this maneuver is 70.12 Joules.
Explanation:
A) Mass of squid with water = 6.50 kg
Mass of water in squid cavuty = 1.55 kg
Mass of squid = ![m_1=6.50 kg- 1.55 kg=4.95 kg](https://tex.z-dn.net/?f=m_1%3D6.50%20kg-%201.55%20kg%3D4.95%20kg)
Velocity achieved by squid = ![v_1=2.60 m/s](https://tex.z-dn.net/?f=v_1%3D2.60%20m%2Fs)
Momentum gained by squid = ![P=m_1v_1](https://tex.z-dn.net/?f=P%3Dm_1v_1)
Mass of water = ![m_2=1.55 kg](https://tex.z-dn.net/?f=m_2%3D1.55%20kg)
Velocity by which water was released by squid = ![v_2](https://tex.z-dn.net/?f=v_2)
Momentum gained by water but in opposite direction = ![P'=m_2v_2](https://tex.z-dn.net/?f=P%27%3Dm_2v_2)
P = P'
![m_1v_1=m_2v_2](https://tex.z-dn.net/?f=m_1v_1%3Dm_2v_2)
![v_2=\frac{m_1v_1}{m_2}=\frac{4.95 kg\times 2.60 m/s}{1.55 kg}=8.30 m/s](https://tex.z-dn.net/?f=v_2%3D%5Cfrac%7Bm_1v_1%7D%7Bm_2%7D%3D%5Cfrac%7B4.95%20kg%5Ctimes%202.60%20m%2Fs%7D%7B1.55%20kg%7D%3D8.30%20m%2Fs)
B) Kinetic energy does the squid create by this maneuver:
Kinetic energy of squid = K.E =![\frac{1}{2}m_1v_1^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dm_1v_1%5E%7B2%7D)
Kinetic energy of water = K.E' = ![\frac{1}{2}m_2v_2^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dm_2v_2%5E%7B2%7D)
Total kinetic energy created by this maneuver:
![K.E+K.E'=\frac{1}{2}m_1v_1^{2}+\frac{1}{2}m_2v_2^{2}](https://tex.z-dn.net/?f=K.E%2BK.E%27%3D%5Cfrac%7B1%7D%7B2%7Dm_1v_1%5E%7B2%7D%2B%5Cfrac%7B1%7D%7B2%7Dm_2v_2%5E%7B2%7D)
![=\frac{1}{2}\times 4.95 kg\times (2.60 m/s)^2+\frac{1}{2}\times 1.55 kg\times (8.30 m/s)^2=70.12 Joules](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%204.95%20kg%5Ctimes%20%282.60%20m%2Fs%29%5E2%2B%5Cfrac%7B1%7D%7B2%7D%5Ctimes%201.55%20kg%5Ctimes%20%288.30%20m%2Fs%29%5E2%3D70.12%20Joules)
Answer:
4. 7.59276
Explanation:
Add up the x components:
Aₓ + Bₓ + Cₓ = 5 − 1.6 + 2.4 = 5.8
Add up the y components:
Aᵧ + Bᵧ + Cᵧ = -2.4 + 3.3 + 4 = 4.9
Use Pythagorean theorem to find the magnitude:
√(x² + y²)
√(5.8² + 4.9²)
√57.65
7.59276
Answer:
Required energy Q = 231 J
Explanation:
Given:
Specific heat of copper C = 0.385 J/g°C
Mass m = 20 g
ΔT = (50 - 20)°C = 30 °C
Find:
Required energy
Computation:
Q = mCΔT
Q = 20(0.385)(30)
Required energy Q = 231 J