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Svet_ta [14]
3 years ago
14

An atom has 20 electrons. Find out

Chemistry
1 answer:
Yanka [14]3 years ago
8 0

Answer:

it's atomic number is 5 and total number is 10

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Solid sodium chloride is formed by the reaction of chlorine gas and solid sodium . write a balanced chemical equation for this r
LuckyWell [14K]
There are no states in the picture, but Na should have a "(s)" after it, and Cl2 should have a "(g)" after it. NaCl should have an "(s)". Chlorine is a diatomic element so it has a "2" subscript on it. 

Hope this helped! :)

4 0
3 years ago
What other simple sugars have the same chemical formula as glucose?
Usimov [2.4K]

Answer:

The answer to your question is:

Explanation:

Other sugars with the same chemical formula as Glucose:

Sugar            Formula            Description

Glucose         C₆H₁₂O₆            It's the most abundant monosaccharide.

Mannose       C₆H₁₂O₆            It's found in plants and some animals.

Fructose        C₆H₁₂O₆            It's the sugar of fruits.

Galactose      C₆H₁₂O₆            It's found in milk.

8 0
3 years ago
Although Rutherford is credited with the famous gold foil scattering experiment, he didn’t actually conduct this experiment hims
DerKrebs [107]
If he was the primary scientist doing it as he did alot of the heavy lifting then yes its ok, but i also think how the others should also me at least mentioned. Or they could just not name the experiment by a person just so its not too biased
3 0
3 years ago
Calculate the ph of a solution containing 0.0451 m potassium hydrogen tartrate and 0.028 m dipotassium tartrate. The ka values f
Marina86 [1]

Given buffer:

potassium hydrogen tartrate/dipotassium tartrate (KHC4H4O6/K2C4H4O6 )

[KHC4H4O6] = 0.0451 M

[K2C4H4O6] = 0.028 M

Ka1 = 9.2 *10^-4

Ka2 = 4.31*10^-5

Based on Henderson-Hasselbalch equation;

pH = pKa + log [conjugate base]/[acid]

where pka = -logKa

In this case we will use the ka corresponding to the deprotonation of the second proton i.e. ka2

pH = -log Ka2 + log [K2C4H4O6]/[KHC4H4O6]

     = -log (4.31*10^-5) + log [0.0451]/[0.028]

pH = 4.15



4 0
3 years ago
Caclulate the pH for a solution with an [H+] = 9.75 x10-4
vovangra [49]

Answer:

pH=3.01

Explanation:

pH=-log[H+]

=-log(9.74x10e-4)

=3.01

3 0
4 years ago
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