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3 years ago

Why is the moon’s surface cratered, but the Earth’s is not

1 answer:

8 0

The comets hit the moon's surface because there is no atmosphere on the moon to protect it. The earth has an atmosphere so it is protected.

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A 25-kg wagon has a momentum of 300kg m/s. What is it’s acceleration?

arsen [322]

The answer is 12 ....

8 0

3 years ago

How are magnetic poles and electrical charges similar? A. Their same forces repel each other, and their opposite forces attract

melomori [17]

Answer:

A. Their same forces repel each other, and their opposite forces attract each other.

Explanation:

As we know by the property of electric charge that similar charges repel each other and opposite charges attracts each other

So here we have similar situation in magnets also

Two similar poles or like poles of magnet i.e. North - North poles or South - South poles always repel each other

And also we can see that opposite poles of magnet each other i.e. North pole and south pole always attract each other.

SO here correct answer is

A. Their same forces repel each other, and their opposite forces attract each other.

8 0

3 years ago

What is 8200 N/m2 expressed in kilopascals?

natima [27]

The S.I. unit for the measure of the pressure is the Pascal (Pa). 1 Pascal corresponds to
$1 Pa = 1 N/m^2$

We can convert the number given by the problem into Pascal:
$8200 N/m^2 = 8200 Pa$

And since $1 Pa = 10^{-3}kPa$ , we have
$8200 Pa = 8200 \cdot 10^{-3}kPa =8.2 kPa$

5 0

3 years ago

A train, traveling at a constant speed of 22.0 m/s, comes to an incline with a constant slope. While going up the incline, the t

Charra [1.4K]

Answer:

123.30 m

Explanation:

Given

Speed, u = 22 m/s

acceleration, a = 1.40 m/s²

time, t = 7.30 s

From equation of motion,

v = u + at

where,

v is the final velocity

u is the initial velocity

a is the acceleration

t is time

V = at + U

using equation v - u = at to get line equation for the graph of the motion of the train on the incline plane

$V_{x} = mt + V_{o}$ where m is the slope

Comparing equation (1) and (2)

$V = V_{x}$

a = m

$U = V_{o}$

Since the train slows down with a constant acceleration of magnitude 1.40 m/s² when going up the incline plane. This implies the train is decelerating. Therefore, the train is experiencing negative acceleration.

a = - 1.40 m/s²

Sunstituting a = - 1.40 m/s² and u = 22 m/s

$V_{x} = -1.40t + 22$