There are 20 number of DVD's in Louis collection
<em><u>Solution:</u></em>
Let "J" be the number of DVD's with Jake
Let "B" be the number of DVD's with Bo
Let "L" be the number of DVD's with Louis
<em><u>Given that Jake owns twice as many DVDs as Louis</u></em>
So we can say,
number of DVD's with Jake = 2(number of DVD's with Loius)
J = 2L ------ eqn 1
<em><u>Given that Bo has sixty fewer DVDs than five times Louis’s collection</u></em>
So we can say,
number of DVD's with Bo = 5 times number of DVD's with Louis - 60
B = 5L - 60 ---- eqn 2
<em><u>Given that Jake and Bo have the same amount of DVDs</u></em>
number of DVD's with Jake = number of DVD's with Bo
J = B ---- eqn 3
<em><u>Let us solve eqn 1, 2, 3 to find value of "L"</u></em>
From eqn 1 and eqn 3,
2L = B ----- eqn 4
Substitute eqn 4 in eqn 2
2L = 5L - 60
2L - 5L = -60
-3L = -60
<h3>L = 20</h3>
Thus there are 20 number of DVD's in Louis collection
