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BabaBlast [244]
3 years ago
7

Help me answer this ASAP

Physics
1 answer:
olga_2 [115]3 years ago
7 0

Answer:

The correct answer is Option A.

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During the deceleration of an ascending elevator, the normal force on the feet of a passenger is _____ her weight. During the de
gizmo_the_mogwai [7]

Answer: Smaller than ; larger than

Explanation:

When the elevator is moving in the upward direction, then the force acting on it is negative in nature because of

N= mg +ma, (g is gravity and a is acceleration)

here ma is negative so the N= mg-ma

Hence, it feels smaller than its original weight.

When the elevator is moving downward , then the force acting will be positive in nature

N= mg+ma,

here ma will be positive so it feels larger the original weight of passenger.

7 0
3 years ago
Anything that can make an object with mass move is called (2 points)
masha68 [24]
The answer is:  [D]:  "force".
________________________________________
Note the formula:  " F = ma"  ;  {"Force = mass * acceleration"}.
______________________________________________________

5 0
3 years ago
Read 2 more answers
A particle moves with a velocity    1 v 5j 3j 6k ms      under influence of a contact force  F 10i 10j 20k N.    
katrin2010 [14]

Answer:

P = 200 W

Explanation:

The expression for the power is

        P = W / t

the job

       W = F d

   

we substitute

      P = F d / t

      P = F. v

We apply this equation to our case where the velocity is

 v = (5 i + 3j + 6k) m / s

and the force is

 F = (10i + 10j +20 k) N

we substitute in the power equation, remember that the scalar product of the unit vectors is

i.i = j.j = k.k = 1 and the other products are zero

    P = 10 5 + 10 3 + 20 6

    P = 200 W

6 0
3 years ago
What does the graph to the right represent?
Nastasia [14]
C the thermal equilibrium

4 0
4 years ago
Read 2 more answers
A wire carrying a current is shaped in the form of a circular loop of radius 3.0mm If the magnetic field strength that this curr
ahrayia [7]

Answer:

Current, I = 5.3 A

Explanation:

It is given that,

Radius of circular loop, r = 3 mm = 0.003 m

Magnetic field strength, B = 1.1 mT = 0.0011 T

We need to find the magnitude of the current that flows through the wire. The magnetic field for a current carrying wire is given by :

B=\dfrac{\mu_o I}{2r}

I=\dfrac{2Br}{\mu_o}

I=\dfrac{2\times 0.0011\ T\times 0.003\ m}{4\pi\times 10^{-7}}

I = 5.25 A

or

I = 5.3 A

So, the magnitude of the current that flows through the wire is 5.3 A. Hence, this is the required solution.

8 0
4 years ago
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