Answer:
11.025 m
87.75 m
Explanation:
Time of flight(T) of a projectile = 2U(sin∅)/g
Where U = initial Velocity, g = acceleration due to gravity, ∅= angle of projection.
Make ∅ the subject of the the equation,
∅ = sin⁻¹[(T× g)/2U]
Where U = 15m/s, T= 3.0 s, g = 9.8 m/s²
∅ = sin⁻¹[(3 × 9.8)/(2×15)]
∅ = sin⁻¹(29.4/30)
∅= sin⁻¹(0.98) = 78.52°
Using the formula for maximum height of a projectile
H = U²sin²∅/2g
H = 15²(sin²78.52)/2 × 9.8
H = 225(0.98 × 0.98)/19.6
H = 216.09/19.6
H = 11.025 m
Range (R) = U²sin2∅/g
R = 15²sin(2×79.52)/9.8
R = 225(0.39)
R =87.75 m
∵ the building is = 11.025 m tall and the base of the building is 87.75m away from where the stone landed.
Answer:
A. structure of the classroom
Explanation:
According to the Creative Curriculum model, the A. structure of the classroom sets the context for teaching and learning.
Creative curriculum model stands to enhance the skill of the students through a structured class room. Creative curriculum goes beyond the rote learning and focuses on big ideas and individual passion of each students.
<span>1080 degrees buddy bye</span>
For Newton's second law, the force F applied to the object of mass m will cause an acceleration a of the body:

So, the acceleration is

The object undergoes through this acceleration for 10 seconds, t=10 s. Since it is an accelerated motion, we can find its final velocity after 10 seconds:

where

is the initial velocity of the object, which is zero since it starts from rest.
Finally we can calculate the final kinetic energy of the object, which is given by