Gravitational potential energy :)
Answer:
Part a)
acceleration = -0.042 m/s/s
Part b)
initial speed = 14.17 m/s
final speed = 5.77 m/s
Explanation:
Part a)
Let the initial velocity of the motorcycle is

now at the end of 80 s let the speed is

after another 120 s let the speed will be

now we know that



also we know that

also we have


now we can say

also we know



Part b)
now we have



so the starting velocity of the trip is

now speed after t = 200 s is given as



Answer:
Distance = 150 meters
Explanation:
Given the following data;
Work done = 6,000 Joules
Force = 40 Newton
To find the total distance covered by the wheelbarrow;
Workdone = force * distance
Substituting into the formula, we have;
6000 = 40 * distance
Distance = 6000/40
Distance = 150 meters
Therefore, the total distance the wheelbarrow was pushed is 150 meters.
Answer:
Pluto.
Explanation:
an observary in Flagstaff, Arizona, discorvered it.
Answer:
Explanation:
Given a school bus.
Let say initially the school bus is traveling with speed "v"
Let assume mass of school bus is "m"
Then, the initial kinetic energy is
K.E_initial = ½mv²
Now, if the initial velocity is tripled,
Then, the new velocity is
v_new = 3v.
Note: the mass of the school does not change it is constant
Then, new kinetic energy is
K.E_new = ½m(v_new)²
v_new = 3v
Then,
K.E_new = ½m(3v)²
K.E_new = ½m × 9v²
K.E_new = 9 × ½mv²
Since K.E = ½mv²
Then,
K.E_new = 9 × K.E
So, the new kinetic energy will be 9 times the initial kinetic energy.
So, option D is correct
D. It will be nine times greater.